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xxTIMURxx [149]
3 years ago
8

Which of the following waves are mechanical waves?

Chemistry
1 answer:
Svetllana [295]3 years ago
7 0
D. Sound waves are a type of mechanical wave
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One of the products when aqueous Na, CO, reacts with aqueous
mixas84 [53]

Answer:

NaNO3

balanced equation - Na2CO3 + Sn(NO3)2 → 2NaNO3 + Sn(CO3)

6 0
2 years ago
What is double bond,triple bond,lone pair and single bond
AlladinOne [14]

In covalent bonds, atoms share electrons. These shared electrons are known as, well, covalent bonds!

In a covalent bond, each atom contributes one electron, meaning that for every bond, there are 2 electrons residing in it.

Definitions:

A single bond is a covalent bond that contains 2 electrons.

A double bond is a covalent bond that contains 4 electrons

A triple bond is a covalent bond that contains 6 electrons

It's very common for atoms to not use all of their electrons while bonding, which means that some will be left out and aren't used in any bonds. These are called lone pairs.

Definition:

A lone pair is a pair of electrons that aren't used in bonding, and therefore remain with its original atom.

5 0
3 years ago
What are examples of a Theory ?
galina1969 [7]

Paradoxes and Russell's Type Theories.

Simple Type Theory and the λ -Calculus.

Ramified Hierarchy and Impredicative Principles.

Type Theory/Set Theory.

Type Theory/Category Theory.

Extensions of Type System, Polymorphism, Paradoxes.

Univalent Foundations.

6 0
3 years ago
Is sweat a chemical? I am curious to know! NO LINKS OR TROLLS
Finger [1]

Answer:

The main reason people perspire is that the evaporation of water can cool our bodies. ... Sweat is chemically similar to plasma, but certain components are selectively retained or excreted.

Explanation:

5 0
3 years ago
An enzyme with molecular weight of 310 kDa undergoes a change in shape when the substrate binds. This change can be characterize
oee [108]

Answer:

(a) r = 6.26 * 10⁻⁷cm

(b) r₂ = 6.05 * 10⁻⁷cm

Explanation:

Using the sedimentation coefficient formula;

s =  M(1-Vρ) / Nf ; where s is sedimentation coefficient, M is molecular weight, V is specific volume of protein, p is density of the solvent, N is Avogadro number, f if frictional force = 6πnr, n is viscosity of the medium, r is radius of particle

s = M ( 1 - Vρ) / N*6πnr

making r sbjct of formula, r =  M (1 - Vρ) / N*6πnrs

Note: S = 10⁻¹³ sec, 1 KDalton = 1 *10³ g/mol, I cP = 0.01 g/cm/s

r = {(3.1 * 10⁵ g/mol)(1 - (0.732 cm³/g)(1 g/cm³)} / { (6.02 * 10²³)(6π)(0.01 g/cm/s)(11.7 * 10⁻¹³ sec)

r = 6.26 * 10⁻⁷cm

b. Using the formula r₂/r₁ = s₁/s₂

s₂ = 0.035 + 1s₁ = 1.035s₁

making r₂ subject of formula; r₂ = (s₁ * r₁) / s₂ = (s₁ * r₁) / 1.035s₁

r₂ = 6.3 * 10⁻⁷cm / 1.035

r₂ = 6.05 * 10⁻⁷cm

8 0
3 years ago
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