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EleoNora [17]
3 years ago
12

Which of the following compounds would contain a total of three carbon atoms? A. 1-butene B. Propane C. 2-triene D. Heptane

Chemistry
2 answers:
svetoff [14.1K]3 years ago
7 0
The answer would be propane
Gnesinka [82]3 years ago
3 0

Answer:

B- Proprane

Explanation:

The propane molecule has three carbon atoms

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Explain why hydrogen can only have 2 valence electrons around it when it bonds to other items. What is the maximum number of bon
lys-0071 [83]

Answer:

In first shell only 2 electrons are present in hydrogen only one electron is present in valence shell. To complete its duplet hydrogen can share lose or gain only one electron to form chemical bond.

Hydrogen can form only one bond.

Explanation:

7 0
3 years ago
Which statements below are an appropriate hypothesis in response to this question? Check all that apply. If a substance changes
Nostrana [21]

Answer:

If a substance undergoes a physical change, then it will retain most of its original properties because no new substance is formed.

If a substance undergoes a chemical change, then it will not retain its original properties because a new substance is formed.

Explanation:

So in shorter words its options 2 and 3

6 0
3 years ago
Read 2 more answers
N2H4+H2O2 ——> N2+H2O coefficient
const2013 [10]

Answer:

N2H4 + 2H2O2 ---->N2 + 4H2O

Explanation:

N=2            N=2

H=6 ->8      H=2 ->8

O=2 -> 4     O=1 -> 4

Add coefficients to hydrogen peroxide on the left and water on the right, so that there is an equal number of hydrogens and oxygens.

3 0
3 years ago
1) When 2.38g of magnesium is added to 25.0cm of 2.27 M hydrochloric acid, hydrogen gas is released.
Andrej [43]

Answer:

a. HCl.

b. 0.057 g.

c. 1.69 g.

d. 77 %.

Explanation:

Hello!

In this case, since the reaction between magnesium and hydrochloric acid is:

Mg+2HCl\rightarrow MgCl_2+H_2

Whereas there is 1:2 mole ratio between them.

a) Here, we can identify the limiting reactant as that yielded the fewest moles of hydrogen gas product via the 1:1 and 2:1 mole ratios:

n_{H_2}^{by\  HCl}=0.025L*2.27\frac{molHCl}{1L}*\frac{1molH_2}{2molHCl}  =0.0284molH_2\\\\n_{H_2}^{by\  Mg}=2.38gMg*\frac{1molMg}{24.3gMg}*\frac{1molH_2}{1molMg}=0.0979molH_2

Thus, since hydrochloric yields fewer moles of hydrogen than magnesium, we realize it is the limiting reactant.

b) Here, we use the molar mass of gaseous hydrogen (2.02 g/mol) to compute the mass:

m_{H_2}=0.0284molH_2*\frac{2.02gH_2}{1molH_2}=0.057gH_2

c) Here, we compute the mass of magnesium associated with the yielded 0.0248 moles of hydrogen:

m_{Mg}^{reacted}=0.0284molH_2*\frac{1molMg}{1molH_2}*\frac{24.3gMg}{1molMg}  =0.690gMg

Thus, the mass of excess magnesium turns out:

m_{Mg}^{excess}=2.38g-0.690g=1.69gMg

d) Finally, we compute the percent yield, considering 0.044 g is the actual yield and 0.057 g the theoretical yield:

Y=\frac{0.044g}{0.057g} *100\%\\\\Y=77\%

Best regards!

8 0
3 years ago
Which is a reason that a chemical engineer would use a rate law for a reaction in a chemical plant?
Harrizon [31]
<span>A.to calculate the amount of product that would form

</span>
5 0
3 years ago
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