Trehalose, sophorose and turanose are disaccharides. Trehalose is found in the cocoons of some insects, sophorose turns up in a
few bean varieties, and turanose is an ingredient in low-grade honey made by bees with indigestion from a diet of pine tree sap. Identify trehalose, sophorose, and turanose (may be none of the above) among the following structures on the basis of the following information.
a. Turanose and sophorose are reducing sugars. Trehalose is non-reducing.
b. Upon hydrolysis, sophorose and trehalose give two molecules each of aldoses. Turanose gives one molecule of an aldose and one molecule of a ketose.
c. The two aldoses that constitute sophorose are anomers to each other.
a. Turanose and sophorose are reducing sugars. Trehalose is non-reducing.
b. Upon hydrolysis, sophorose and trehalose give two molecules each of aldoses. Turanose gives one molecule of an aldose and one molecule of a ketose.
c. The two aldoses that constitute sophorose are anomers to each other.
1 answer:
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Answer:
75.9 grams of salt
Explanation:
The reaction is the following:
2Na(s) + Cl₂(g) → 2NaCl(s) (1)
We have:
m(Na): the mass of sodium = 30 g
V(Cl₂): the volume of the chlorine gas at STP = 60 L
So, to find the mass of NaCl we need to calculate the number of moles of Na and Cl₂.
The number of moles of Cl₂ can be found by the Ideal gas law equation:
Where:
P: is the pressure = 1 atm (at STP)
R: is the gas constant = 0.082 L*atm/(K*mol)
T: is the temperature = 273 K (at STP)
Now we need to find the limiting reactant. From the stoichiometric relation between Na and Cl₂ (equation 1), we have that 2 moles of Na react with 1 mol of Cl₂, so:
Since we have 1.30 moles of Na, the limiting reactant is Na.
Finally, we can find the number of moles of NaCl and its mass.
Therefore, would be formed 75.9 grams of salt.
I hope it helps you!