Answer:
7.23 J
Explanation:
Step 1: Given data
- Mass of graphite (m): 566.0 mg
- Initial temperature: 5.2 °C
- Final temperature: 23.2 °C
- Specific heat capacity of graphite (c): 0.710J·g⁻¹K⁻¹
Step 2: Calculate the energy required (Q)
We will use the following expression.
Q = c × m × ΔT
Q = 0.710J·g⁻¹K⁻¹ × 0.5660 g × (23.2°C-5.2°C)
Q = 7.23 J
The existence of spectra can help the existence of atoms by expanding and multiplying in the law of London Dispersion
They are combined 50% from your mom and the other from your dad
If we let x be the number of sample which contains the atoms of carbon (C). Given that according to study, the amount of atoms in carbon sample that are C-13 atoms is 1.07%, the mathematical set-up that would represent the sample is,
= (0.0107)(C)
