Sorry bro people do this22.2 pls
Answer:
Answer explained below
Explanation:
The value of here is 9
The value of there is hexadecimal value of DECO here, d = 0x39 aaaa (aaaa is the memory address of here )
We have the object code :-
let's take there address is 0x0007
0x0005 BR there :- 0x120020
0x0007 here: .WORD 9
310003 there: DECO here,d - 0x390007
310005 STOP
.END
A. All the answers are correct (All of the above).
Answer:
D.telling your passengers where you are going
Answer:
μb = 0.096
μc = 0.073
Explanation:
member AB:
-800( 4/3 ) + Nb (2) = 0
Nb (2) = 3200/3
Nb = 533.3N
Post BC:
summation of force along the y axis=0
Nc + Nb + 150(3/5 ) -50(9.81)=0
Nc + 533.3 + 150(3/5 ) -50(9.81)=0
Nc = 933.83 N
Also (-4/5)(150)(3) + Fb(0.7)= 0
Fb = (4/5)(150)(3)/0.7 = 51.429 N
Likewise alog the x axis,
4/5(150) - Fc -Fb = 0
4/5(150) - Fc -51.429 = 0
Fc = 4/5(150) -51.429 =68.571 N
μb = Fb/Nb = 51.429/533.3 = 0.096
μc = Fc/Nc = 68.571 / 933.83 = 0.073