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Amiraneli [1.4K]
3 years ago
11

Can someone plz help me?? See the picture below.

Chemistry
1 answer:
GaryK [48]3 years ago
3 0
Acid rain has no effect on limestone. So nothing happens.
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Walter gets a paper back in lab with “-2.75% error” written on it. He found the mass of an object to be 100.7 grams. What should
stepan [7]
0.0275x100.7= 2.8(approximately). 100.7-2.8=97.9grams
3 0
4 years ago
Why would "not flammable" be a chemical property rather than a physical property ?
Dmitrij [34]
When something is flammable, it burns and burning is a chemical property since the compounds are being broken down and gas is released. If something is non-falammable, it would then be a chemical property as well since the chemical makeup would not be broken by a flame. (I apologize if my answer is a bit broad or unspecific)
4 0
3 years ago
If 10.0 moles of sulfur dioxide react with excess chlorine gas, what is the theoretical yield (in grams) of CI2O produced?
xz_007 [3.2K]

Answer:

869 g Cl₂O

Explanation:

To find the theoretical yield of Cl₂O, you need to (1) convert moles SO₂ to moles Cl₂O (via mole-to-mole ratio from reaction coefficients) and then (2) convert moles Cl₂O to grams Cl₂O (via molar mass). It is important to arrange the conversions/ratios in a way that allows for the cancellation of units (the desired unit should be in the numerator). The final answer should have 3 sig figs to reflect the sig figs of the given amount (10.0 moles).

1 SO₂ (g) + 2 Cl₂ (g) ----> 1 SOCl₂ (g) + 1 Cl₂O (g)

Molar Mass (Cl₂O): 2(35.453 g/mol) + 15.998 g/mol

Molar Mass (Cl₂O): 86.904 g/mol

10.0 moles SO₂         1 mole Cl₂O            86.904 g
------------------------  x  ----------------------  x  ------------------  = 869 g Cl₂O
                                    1 mole SO₂              1 mole

6 0
2 years ago
What is the difference between active transport and facilitated diffusion?
Vaselesa [24]

Answer:

Active transport is an active process. Thus, it requires energy. Whereas facilitated diffusion is a passive process and does not require energy.

Explanation:

Hope this helps:)

6 0
3 years ago
Read 2 more answers
The half-life of a pesticide determines its persistence in the environment. A common pesticide degrades in a first-order process
denis23 [38]

Answer:

0.1066 hours

Explanation:

A common pesticide degrades in a first-order process with a rate constant (k) of 6.5 1/hours. We can calculate its half-life (t1/2), that is, the times that it takes for its concentration to be halved, using the following expression.

t1/2 = ln2/k

t1/2 = ln2/6.5 h⁻¹

t1/2 = 0.1066 h

The half-life of the pesticide is 0.1066 hours.

7 0
4 years ago
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