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Alik [6]
2 years ago
10

Differenciate between adsorption and absorption.

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ty! ~​
Chemistry
2 answers:
SVETLANKA909090 [29]2 years ago
5 0

Very easy difference~√

and i don't answer simple questions.

blagie [28]2 years ago
4 0

Answer:

Adsorption is the adhesion of a liquid or gas on the surface of a solid material, forming a thin film on the surface While Absorption is the process of being swallowed up or by being absorbed

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Estimate ΔH for the reaction: C2H6(g) + Cl2(g)--> C2H5Cl(g) + HCl(g) given the following average bond energies (in kJ/mol): C
Leno4ka [110]

Explanation:

The reaction equation will be as follows.

    C_{2}H_{6}(g) + Cl_{2}(g) \rightarrow C_{2}H_{5}Cl(g) + HCl(g)

Using bond energies, expression for calculating the value of \Delta H is as follows.

    \Delta H = \sum B.E_{reactants} - \sum B.E_{products}

On reactant side, from C_{2}H_{6} number of bonds are as follows.

C-C bonds = 1

C-H bonds = 6

From Cl_{2}; Cl-Cl bonds = 1

On product side, from C_{2}H_{5}Cl number of bonds are as follows.

C-C bonds = 1

C-H bonds = 5

C-Cl bonds = 1

From HCl; H-Cl bonds = 1

Hence, using the bond energies we will calculate the enthalpy of reaction as follows.

  \Delta H = \sum B.E_{reactants} - \sum B.E_{products}

  =[(1 \times 348 kJ/mol) + (6 \times 414 kJ/mol) + (1 \times 242 kJ/mol)] - [(1 \times 348 kJ/mol) + (5 \times 414 kJ/mol) + (1 \times 327 kJ/mol) + (1 \times 431 kJ/mol)]            = -102 kJ/mol

Thus, we can conclude that change in enthalpy for the given reaction is -102 kJ/mol.

5 0
3 years ago
What's the difference between long period and short period comets?
just olya [345]

Answer:

100 years

Explanation:

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6 0
4 years ago
Na2CO3 → Na2O + CO2<br> Balance
Andre45 [30]

Answer: Na2CO3 → Na2O + CO2 is already balanced

Explanation:

See answer.

3 0
3 years ago
What is the mass percent of carbon in propanoic acid (C2H5COOH)? (The molar mass of C = 12.01, H = 1.0079, and O = 16.00.)
Yuri [45]
Mass percent is calculated by the ratio of the mass of the substance in a sample over the total mass of the sample multiplied by 100. Assuming 1 mol of the acid, we will have 74.09 g. We do as follows:

% by mass C = 3 ( 12.01) / 74.09 x 100 = 48.63% C
5 0
3 years ago
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What is a digestive system​
Andre45 [30]

Answer:

your belly

Explanation:

6 0
3 years ago
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