1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Artyom0805 [142]
3 years ago
9

Which of the following phases of matter has a fixed shape and volume

Chemistry
2 answers:
nikdorinn [45]3 years ago
7 0

<u>Answer:</u>

<em>Solid phase has a fixed shape and volume</em>

<em></em>

<u>Explanation:</u>

A solid has a definite volume and a definite shape.  

A liquid a definite volume and no definite shape.  

A gas no definite volume and no definite shape.

<u>Solids </u>

1. Solids have a definite volume and definite shape

2. The particles present in a solid are very closely packed since the intermolecular forces between them are very strong. The molecules do not move apart.  

<u>Liquids </u>

1. Liquids have a definite volume and no definite shape

2. The particles present in a liquid are closely packed since the intermolecular forces holds the molecules close together. The molecules slide over each other.

3. Liquids take up the shape of the container

<u>Gases </u>

1. Gases have no definite volume and no definite shape

2. The particles present in a gas are very loosely packed since the intermolecular forces are very weak.

3. There are no attractive forces between the molecules.

4. Gases spread through the container

kodGreya [7K]3 years ago
4 0

A matter in the solid phase has a fixed shape and volume.

You might be interested in
Calculate the number of grams in sodium in 7.6g of Na2C6H6O7 (sodium hydrogen citrate) express your answer using two significant
Katen [24]

Answer:

Explanation:

the molecular mass of Na2C6H6O7 =236 g\mole it has a sodium that has 23 g/mole so 7.6 g of Na2C6H6O7 has x of sodium mass

  236 g/mole ⇒  23g/mole

<h2>   7.6 g  ⇒    ˣ    </h2>

7.6 x 23 ÷ 236  = 74.07×10-2 grams of sodium

<h2 />
7 0
3 years ago
How much time would it take to distribute one avagadro's number of wheat grains if 10^10 grains are A)1.9*10^2 years B)1.9*10^10
Makovka662 [10]

Answer:

It takes  1.9 \times 10^{6} years to distribute all the grains.

Explanation:

In one second, 10^{10} grains of wheat are distributed.

We are supposed to find the time it would take to Distribute Avogadro number of grains.

1 avogadro number = 6.022 \times 10^{23}

Number of grains distributed in 1 day = 86400 \times 10^{10}

                                                             = 8.64 \times 10^{14}

Number of grains distributed in 1 year= 8.64 \times 10^{14} \times 365

                                 = 3.1536 \times 10^{17}

Time taken = \frac{Number of grains to be distributed}{grains distributed in 1 year}

            = \frac {6.022 \times 10^{23}}{3.1536\times 10^{17}}

            = 1.9 \times 10^{6}

7 0
3 years ago
What is the mass in grams of 5.00moles of CH4?
anastassius [24]

Answer:

1. 80g

2. 1.188mole

Explanation:

1. We'll begin by obtaining the molar mass of CH4. This is illustrated below:

Molar Mass of CH4 = 12 + (4x1) = 12 + 4 = 16g/mol

Number of mole of CH4 from the question = 5 moles

Mass of CH4 =?

Mass = number of mole x molar Mass

Mass of CH4 = 5 x 16

Mass of CH4 = 80g

2. Mass of O2 from the question = 38g

Molar Mass of O2 = 16x2 = 32g/mol

Number of mole O2 =?

Number of mole = Mass /Molar Mass

Number of mole of O2 = 38/32

Number of mole of O2 = 1.188mole

6 0
3 years ago
For a lake in Michigan, researchers have determined that largemouth bass feed on smaller fish, which in turn feed on zooplankton
allsm [11]

Answer:

the expected decline in largemouth bass is 3,000 kg.

Option d) 3,000 kg is the correct answer.

Explanation:

Given the data in the question;

In 2016, there was 600,000 kg of zooplankton in the lake.

In 2017, an accidental runoff of insecticide near the lake caused a 50 percent decline of the zooplankton population in the lake.

Now,

The remaining mass of zooplankton  after the 50% decline will be;

⇒ 600,000 kg zooplankton  × 50%

⇒ 600,000 × 50/100

⇒ 300,000 kg of zooplankton

Now, with 10 percent trophic efficiency;  smaller fish directly feed on zooplankton; decline in smaller fish mass will be;

⇒ 300,000 kg × 10%

⇒ 300,000 × 10/100

⇒  30000 kg

Finally, with 10 percent trophic efficiency, largemouth bash directly feed on smaller fish, so the expected decline in mass of largemouth bash will be;

⇒ 30000 kg × 10%

⇒ 30000 kg × 10/100

⇒ 3,000 kg

Therefore, the expected decline in largemouth bass is 3,000 kg.

Option d) 3,000 kg is the correct answer.

7 0
3 years ago
The specific heat of liquid ethyl alcohol is 2.42 j/g C and its density of 0.7893 g/mL. A piece of solid sliver (specific heat 0
Doss [256]
MAg*cAg*(T1-T)=ρalc*Valc*calc*(T-T2)
mAg=?(g)
cAg=0.24J/gC
T1=95
T=23.5
Valc=25.6ml
ρalc=0.7893g/ml
T2=19.27
use wollframalpha or calculator
6 0
3 years ago
Read 2 more answers
Other questions:
  • what mass of KCI ( solubility= 34.0 KCI/100 g water at 20 degrees celsius) can dissolve in 3.0x 10² g of water?
    13·1 answer
  • (a) 4.64 x 1024 atoms Bi into grams
    8·1 answer
  • What does the (lll) in iron ion mean
    9·1 answer
  • The Lewis structure for methane, CH4 is shown. How many valence electrons does each hydrogen atom in the molecule have?​
    9·1 answer
  • If a room requires 25.4 square yards of carpeting, what is the area of the floor in units of ft2? (3 ft = 1 yd)
    10·1 answer
  • 12. Draw an energy curve for a chemical reaction that begins at 30 kj and has an activation energy of
    12·1 answer
  • What is the mass of 3.6 x 10∧24 atoms of Zinc (Zn)?
    11·1 answer
  • Create the Equation: What is the Percent Yield of Ammonia (NH3) if 11.8 g is recovered in a reaction with 7.02 x 10^23 molecules
    5·1 answer
  • PLEASEEEE HELP I WILL GIVE 30 POINTS Cobalt
    11·1 answer
  • Calculate the volume occupied by 10 moles of hydrogen gas at 145K and 705 Torr.
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!