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Artyom0805 [142]
3 years ago
9

Which of the following phases of matter has a fixed shape and volume

Chemistry
2 answers:
nikdorinn [45]3 years ago
7 0

<u>Answer:</u>

<em>Solid phase has a fixed shape and volume</em>

<em></em>

<u>Explanation:</u>

A solid has a definite volume and a definite shape.  

A liquid a definite volume and no definite shape.  

A gas no definite volume and no definite shape.

<u>Solids </u>

1. Solids have a definite volume and definite shape

2. The particles present in a solid are very closely packed since the intermolecular forces between them are very strong. The molecules do not move apart.  

<u>Liquids </u>

1. Liquids have a definite volume and no definite shape

2. The particles present in a liquid are closely packed since the intermolecular forces holds the molecules close together. The molecules slide over each other.

3. Liquids take up the shape of the container

<u>Gases </u>

1. Gases have no definite volume and no definite shape

2. The particles present in a gas are very loosely packed since the intermolecular forces are very weak.

3. There are no attractive forces between the molecules.

4. Gases spread through the container

kodGreya [7K]3 years ago
4 0

A matter in the solid phase has a fixed shape and volume.

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It can be either they can have a negative or positive charge more specifically negatively charged molecule would called an anion and a positive one would be cation.

3 0
3 years ago
Question 23 (3 points)
Mice21 [21]

Answer:

<h2>The answer is 3.0 mL</h2>

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

volume =  \frac{mass}{density}  \\

From the question

mass of aluminum = 8.1 g

density = 2.7 g/mL

It's volume is

volume =  \frac{8.1}{2.7}  \\

We have the final answer as

<h3>3.0 mL</h3>

Hope this helps you

3 0
3 years ago
Lipid vesicles are formed containing pure water. If these vesicles are transferred to a solution that contains a rather high con
NNADVOKAT [17]

Answer:

The question is not complete, the complete question should be "Lipids vesicles are formed containing pure water. If these vesicles are transferred to a solution that contains a rather high concentration of solutes, the solution outside the vesicle is said to be Hypertonic. True or False"

The answer is True

Explanation:

This is because  it contains greater concentration of solutes on the outside of the cell than the increase.

In other words hypertonic solutions have more concentrate of solutions on the outside than the inside.

3 0
3 years ago
Suppose a 2.95 g of potassium iodide is dissolved in 350. mL of a 62.0 m M aqueous solution of silver nitrate. Calculate the fin
STALIN [3.7K]

Answer : The final molarity of iodide anion in the solution is 0.0508 M.

Explanation :

First we have to calculate the moles of KI and AgNO_3.

\text{Moles of }KI=\frac{\text{Mass of }KI}{\text{Molar mass of }KI}

Molar mass of KI = 166 g/mole

\text{Moles of }KI=\frac{2.95g}{166g/mole}=0.0178mole

and,

\text{Moles of }AgNO_3=\text{Concentration of }AgNO_3\times \text{Volume of solution}=0.0620M\times 0.350L=0.0217mole

Now we have to calculate the limiting and excess reagent.

The given chemical reaction is:

KI+AgNO_3\rightarrow KNO_3+AgI

From the balanced reaction we conclude that

As, 1 mole of KI react with 1 mole of AgNO_3

So, 0.0178 mole of KI react with 0.0178 mole of AgNO_3

From this we conclude that, AgNO_3 is an excess reagent because the given moles are greater than the required moles and KI is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of AgI

From the reaction, we conclude that

As, 1 mole of KI react to give 1 mole of AgI

So, 0.0178 moles of KI react to give 0.0178 moles of AgI

Thus,

Moles of AgI = Moles of I^- anion = Moles of Ag^+ cation = 0.0178 moles

Now we have to calculate the molarity of iodide anion in the solution.

\text{Concentration of }AgNO_3=\frac{\text{Moles of }AgNO_3}{\text{Volume of solution}}

\text{Concentration of }AgNO_3=\frac{0.0178mol}{0.350L}=0.0508M

Therefore, the final molarity of iodide anion in the solution is 0.0508 M.

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3 years ago
What is a zone of weak, variable winds located at 30 degrees north and 30 degrees south?
timurjin [86]

Answer:

Horse latitude, trade winds

Explanation:

  • The area of the low pressure or the calm consists of the variable light winds that blow near the equator are known to the marines as the doldrums and they form a circuital pattern near the earth atmosphere.
  • Forms at a center of the near the higher pressure systems called as the horse latitudes where the  trade winds at the surface are weak and variable and this zone is found generally in latitudes of the 30° North and South of the equator and move in an east to west direction.

4 0
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