Answer:
A molecule is the smallest particle in a chemical element or compound that has the chemical properties of that element or compound. Molecules are made up of atoms that are held together by chemical bonds. These bonds form as a result of the sharing or exchange of electrons among atoms.
Explanation:
Answer:
Valence of iron in FeS2
Let the valency of iron be x
x+2(oxidation number of Sulphur)=0 as their is no charge on FeS2
As sulphur belongs to Group VI (chalcogens) so the valency/oxidation number of Sulphur is -2
x+2(-2)=0
x-4=0
x=4
So the valency/oxidation number of iron in FeS2 is +4
Explanation:
Hope it will help you monkey ^_^ it's crab
Answer:
Pb⁺²(aq) + CO₃⁻²(aq) → PbCO₃ (s)
In net ionic equation we cancel the ions that have equal moles on both sides so Na⁺¹ and NO₃⁻¹ have equal moles on both sides so we canceled them.
Explanation:
Net ionic equation:
In net ionic equation we only write the ions that are involved in reaction. If the system have same moles of ions in initial and final stages we cancel them as they have the same amount and are present in ionic form in the reaction medium. To formulate an ionic equation we just cancel the ions which have the same moles in initial and final stages.
Chemical equation:
Pb(NO₃)₂ (aq) + Na₂CO₃(aq) → PbCO₃ (s) + NaNO₃ (aq)
Balanced chemical equation:
In a balanced chemical equation we write the reactants and products in molecular form with number of moles.
Pb(NO₃)₂ (aq) + Na₂CO₃(aq) → PbCO₃ (s) + 2NaNO₃ (aq)
Ionic equation:
In ionic equation we write the equation in ionic form. It involves all the ions which will produce when we add any ionic compound in reaction medium.
Pb⁺² +2NO₃⁻¹ + CO₃⁻² + 2Na⁺¹ → PbCO3 (s) + 2NO₃⁻¹ (aq) + 2Na⁺¹ (aq)
Net ionic equation
In net ionic equation we cancel the ions that have equal moles on both sides. As we can see in the above ionic equation that Na⁺¹ and NO₃⁻¹ have equal moles on both sides so we canceled them.
Pb⁺²(aq) + CO₃⁻²(aq) → PbCO₃ (s)
I believe the correct answer from the choices listed above is the first option. There are about 840 candies present on all vans present. We calculate it by multiplying the number of total passengers by the number of candies each passenger is carrying. Hope this answers the question.
Answer:
Hey there.. the question is not proper. Please give the whole question