All categories

3 years ago

A 2.47 kg book is dropped from a height of +2.6 m.

Physics

1 answer:

icang [17]3 years ago

5 0

9.8 m/s^2

from brainly

josh207

Ambitious

17 answers

2.3K people

The answer is 9.8 ms^-2, because there is only one force acting on the object so the acceleration will be numerically equal to the gravitational field strength.

gravity = 9.8 m/s^2

2.47 * 9.8 = 24.206 N

You might be interested in

Assume that the surface temperature of the lightbulb filament when it is plugged into an outlet of 120 V is about 3000 K and the

myrzilka [38]

Answer:

A= $8.7\times 10^{-7}m^{2}$

Explanation:

We have given power =40 W but only 10% of this power is used so actual power $P=\frac{40\times 10}{100}=4 W$

We know that from Stefan's law $p=\sigma AT^4$ where $\sigma$ is Boltzmann constant which value is $5.6\times 10^{-8}Wm^{-2}K^{-4}$

So $4=5.67\times 10^{-8}\times A\times 3000^4$

A= $8.7\times 10^{-7}m^{2}$

4 0

3 years ago

Read 2 more answers

Convert 23 miles into feet. **There are 5280 feet in 1 mile** *

zhenek [66]

Answer:

121440 feet is 23 miles.

5280 x 23= 121440

To check your answer just divide 121440 by 5280, which gives you 23.

Hopefully this helps you!

8 0

3 years ago

A 100 kg marble slab falls off a skyscraper and falls 200 m to the ground without hitting anyone. Its fall stops within millisec

Radda [10]

Answer:

Δ T = 2.28°C

Explanation:

given,

mass of marble = 100 Kg

height of fall = 200 m

acceleration due to gravity = 9.8 m/s²

C_marble = 860 J/(kg °C)

using conservation of energy

Potential energy = heat energy

$m g h = m C_{marble}\Delta T$

$g h =C_{marble}\Delta T$

$\Delta T= \dfrac{g h}{C_{marble}}$

$\Delta T= \dfrac{9.8 \times 200}{860}$

Δ T = 2.28°C

7 0

4 years ago

Balance the equation- Al+Mn02 ———-> Mn + Al2O3

joja [24]

Answer:

Explanation:

3 0

3 years ago

An infinite sheet of charge, oriented perpendicular to the x-axis, passes through x = 0. It has a surface charge density σ1 = -2

pishuonlain [190]

Answer:

$E_{total}=4.82*10^6N/C$

vector with direction equal to the axis X.

Explanation:

We use the Gauss Law and the superposition law in order to solve this problem.

Superposition Law: the Total Electric field is the sum of the electric field of the first infinite sheet and the Electric field of the second infinite sheet:

$E_{total}=E_1+E_2$

Thanks Gauss Law we know that the electric field of a infinite sheet with density of charge σ is:

$E=\sigma/(2\epsilon_o)$

Then:

$E_{total}=(\sigma_1+\sigma_2)/(2\epsilon_o)=(-2.7*10^{-6}+88*10^{-6})/(2*8.85*10^{-12})=4.82*10^6N/C$

This electric field has a direction in the axis perpendicular to the sheets, that means it has the same direction as the axis X.

7 0

3 years ago

Read 2 more answers