3 years ago

When a postitive charge is placed in a electric field the field will

1 answer:

5 0

the electric field direction about a positive source charge is always directed away from the positive source. And the electric field direction about a negative source charge is always directed toward the negative source.

You might be interested in

Examples of shape in the classroom

zavuch27 [327]

Answer:

rectangle desk,

Explanation:

6 0

3 years ago

A man stands still on a moving walkway that is going the speed of 0.4 m a second to the east what is the velocity of the man acc

MaRussiya [10]

Answer:

gtfcddcghjhgtthghyy

Explanation:

5 0

3 years ago

What's the thrust force of 20,000N

nika2105 [10]

Answer:

895g

Explanation:

5 0

3 years ago

______ clouds are formed when air masses rise vertically in the atmosphere.

zhannawk [14.2K]

a) Cumulus is 100% the correct answer

6 0

3 years ago

Read 2 more answers

At a certain place, Earth's magnetic field has magnitude B =0.703 gauss and is inclined downward at an angle of 75.4° to the hor

Irina18 [472]

Answer:

The charge flows in coulombs is

$dq=1.843x10^{-5}C$

Explanation:

The current magnitude of current is given by the resistance and the induced Emf as:

$I=N*\frac{dF}{Rdt}$

$\frac{dq}{dt}=\frac{dF}{Rdt}=dq=N*\frac{dF}{R}$

$dq=\frac{N*\beta*A*(Cos(\alpha_f)-Cos(\alpha_i}{R}$

$N=1300$ , $\beta=0.703$ , $A=\pi*r^2=\pi*0.10^2=0.01\pi m^2$ , $R=99.4+202=301.4$ Ω

$\alpha_f=14.6$ , $\alpha_i=165.4$

Replacing :

$dq=\frac{1300*0.703x10^{-4}*0.01\pi*(0.9667-(-0.9667))}{202+99.4}$

$dq=1.843x10^{-5}C$

5 0

3 years ago