Answer:
0.58 days is needed
Explanation:
Gravitational energy change from a height change equal to 8848 m for a mass of 53 kg is:
m*g*h = 53*9.81*8848 = 4600340.64 J = 4600.34 kJ
4.184 kJ are equivalent to 1 kcal, then:
4.184 kJ / 4600.34 kJ = 1 kcal / x kcal
x = 4600.34/4.184
x = 1099.5 kcal or large calories
The diet is 1910 kcal/day, then you need 1099.5/1910 = 0.58 days
15 minutes because 60 minutes divided by 4 mph equals 15 minutes per mile
The rock's height <em>y</em> at time <em>t</em> is given by
<em>y</em> = 45 m + (7.2 m/s) <em>t</em> - 1/2 <em>g</em> <em>t </em>²
where <em>g</em> = 9.80 m/s² is the magnitude of the acceleration due to gravity. Set <em>y</em> = 0 and solve for <em>t</em> :
0 = 45 m + (7.2 m/s) <em>t</em> - 1/2 <em>g</em> <em>t </em>² → <em>t</em> ≈ 3.9 s
Answer:
Initial velocity (u) = 40 m/s
Distance travel in last 5 seconds = 100 m
Explanation:
Given:
Acceleration (a) = 8 m/s²
Final velocity (v) = 0 m/s
Find;
1] Initial velocity before 5 sec
2] Distance travel in last 5 seconds
Computation:
1] Initial velocity before 5 sec
v = u + at
0 = u + (-8)(5)
u - 40 = 0
Initial velocity (u) = 40 m/s
2] Distance travel in last 5 seconds
s = ut + (1/2)(a)(t²)
s = (40)(5) + (1/2)(-8)(5²)
s = 200 - 100
Distance travel in last 5 seconds = 100 m
