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3 years ago

One of the leading causes of permanent damage leading to hearing impairment is _____.

Physics

2 answers:

Dafna1 [17]3 years ago

8 0

<h3><u>Answer;</u></h3>

loud noise that damages hair cells

One of the leading causes of permanent damage leading to hearing impairment is<em><u> loud noise that damages hair cells</u></em>.

<h3><u>Explanation</u>;</h3>

Loud noise is the among the leading cause of permanent damage of the ear which impairs hearing.
<em><u>Loud noise may cause damage to the cells and the membranes in the cochlea of the ear. Listening to loud noise for a very long time overworks the hair cells that may make them to die.</u></em>
The damage to the cochlea of the ear causes permanent hearing loss since all or part of the inner ear has been damaged.

Maslowich3 years ago

6 0

One of the leading causes of hearing impairment that's due to damage
of the ear machinery is prolonged exposure to loud noise or loud music,
which damage the tiny hair cells that stimulate nerve endings in the inner ear.
Trust me.

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A satellite is always being pulled by gravity.<br> a. True<br> b. False

tangare [24]

This is true. Gravity is constantly pulling on anything and everything (even light!), no matter how far away it is from another object.

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3 years ago

At the bottom of its path, the ball strikes a 2.30 kg steel block initially at rest on a frictionless surface. The collision is

Triss [41]

Answer:

(a). The speed of the ball after collision is 2.01 m/s.

(b). The speed of the block after collision 1.11 m/s.

Explanation:

Suppose, A steel ball of mass 0.500 kg is fastened to a cord that is 50.0 cm long and fixed at the far end. The ball is then released when the cord is horizontal.

Given that,

Mass of steel block = 2.30 kg

Mass of ball = 0.500 kg

Length of cord = 50.0 cm

We need to calculate the initial speed of the ball

Using conservation of energy

$\dfrac{1}{2}mv^2=mgl$

$v=\sqrt{2gl}$

Put the value into the formula

$u=\sqrt{2\times9.8\times50.0\times10^{-2}}$

$u=3.13\ m/s$

The initial speed of the ball $u_{1}=3.13\ m/s$

The initial speed of the block $u_{2}=0$

(a). We need to calculate the speed of the ball after collision

Using formula of collision

$v_{1}=(\dfrac{m_{1}-m_{2}}{m_{1}+m_{2}})u_{1}+(\dfrac{2m_{2}}{m_{1}+m_{2}})u_{2}$

Put the value into the formula

$v_{1}=(\dfrac{0.5-2.30}{0.5+2.30})\times3.13$

$v_{1}=-2.01\ m/s$

Negative sign shows the opposite direction of initial direction.

(b). We need to calculate the speed of the block after collision

Using formula of collision

$v_{2}=(\dfrac{2m_{1}}{m_{1}+m_{2}})u_{1}+(\dfrac{m_{1}-m_{2}}{m_{1}+m_{2}})u_{2}$

Put the value into the formula

$v_{2}=(\dfrac{2\times0.5}{0.5+2.30})\times3.13+0$

$v_{2}=1.11\ m/s$

Hence, (a). The speed of the ball after collision is 2.01 m/s.

(b). The speed of the block after collision 1.11 m/s.

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3 years ago

A cyclist turns a corner with a radius of 50m at a speed of 10m/s. What is the cyclist's acceleration?

garri49 [273]

Answer:

2 m/s^2

Explanation:

a = v^2/r

a = (10m/s)^2 / 50m

a = 2 m/s^2

Leave a like and mark brainliest if this helped

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2 years ago

Three resistors of 100 W, 3900 W, and 1000 W are connected in series across a 200-V battery. What is the voltage drop across the

Gala2k [10]

Answer:

40 V

Explanation:

I will assume that the resistors are

100 and 3900 and 1000 OHMS <=====(NOT W)

In series , the resistances add together 100 + 3900 + 1000 = 5000 ohms total

V = IR

I = V / R so the total current will be 200 v / 5000 ohms = .04 amps

this is the current through all of the resistors

so for the 1000 ohm resistor V = IR .04 (1000) = 40 V

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2 years ago

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IRISSAK [1]

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3 years ago

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