1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
sasho [114]
3 years ago
6

One of the leading causes of permanent damage leading to hearing impairment is _____.

Physics
2 answers:
Dafna1 [17]3 years ago
8 0
<h3><u>Answer;</u></h3>

loud noise that damages hair cells

One of the leading causes of permanent damage leading to hearing impairment is<em><u> loud noise that damages hair cells</u></em>.

<h3><u>Explanation</u>;</h3>
  • Loud noise is the among the leading cause of permanent damage of the ear which impairs hearing.
  • <em><u>Loud noise may cause damage to the cells and the membranes in the cochlea of the ear. Listening to loud noise for a very long time overworks the hair cells that may make them to die.</u></em>
  • The damage to the cochlea of the ear causes permanent hearing loss since all or part of the inner ear has been damaged.
Maslowich3 years ago
6 0
One of the leading causes of hearing impairment that's due to damage
of the ear machinery is prolonged exposure to loud noise or loud music,
which damage the tiny hair cells that stimulate nerve endings in the inner ear.               
Trust me.
You might be interested in
Boyles law<br> squeezing a balloon is one way to burst it. Why? ...?
KiRa [710]
According to Boyle's Law,  volume is inversely proportional to pressure. It means if the volume of a gas goes up the pressure goes down and if the volume of the gas goes up the pressure goes down. When the pressure of air inside the inflated balloon is more than the atmospheric pressure outside the balloon. And also when the density inside is greater than the density outside. The molecules inside the balloon move and bang around the inner walls which produces force, which provides the pressure of an enclosed air.
6 0
4 years ago
Rock X is released from rest at the top of a cliff that is on Earth. A short time later, Rock Y is released from rest from the s
frosja888 [35]

Answer:

C) True. S increases with time, v₁ = gt and v₂ = g (t-t₀)  we see that for the same t v₁> v₂

Explanation:

You have several statements and we must select which ones are correct. The best way to do this is to raise the problem.

Let's use the vertical launch equation. The positive sign because they indicate that the felt downward is taken as an opponent.

Stone 1

    y₁ = v₀₁ t + ½ g t²

    y₁ = 0 + ½ g t²

Rock2

It comes out a little later, let's say a second later, we can use the same stopwatch

     t ’= (t-t₀)

    y₂ = v₀₂ t ’+ ½ g t’²

    y₂ = 0 + ½ g (t-t₀)²

    y₂ = + ½ g (t-t₀)²

Let's calculate the distance between the two rocks, it should be clear that this equation is valid only for t> = to

    S = y₁ -y₂

    S = ½ g t²– ½ g (t-t₀)²

    S = ½ g [t² - (t²- 2 t to + to²)]  

    S = ½ g (2 t t₀ - t₀²)

    S = ½ g t₀ (2 t -t₀)

This is the separation of the two bodies as time passes, the amount outside the Parentheses is constant.

For t <to.  The rock y has not left and the distance increases

For t> = to.  the ratio (2t/to-1)> 1 therefore the distance increases as time

passes

Now we can analyze the different statements

A) false. The difference in height increases over time

B) False S increases

C) Certain s increases with time, v₁ = gt and V₂ = g (t-t₀) we see that for the same t   v₁> v₂

3 0
4 years ago
During an experiment of momentum, trolley, X, of mass (2.34 ± 0.01) kg is moving away from another trolley, Y, of mass (2.561 ±
Alla [95]

Answer:

P = 1 (14,045 ± 0.03 )  k gm/s

Explanation:

In this exercise we are asked about the uncertainty of the momentum of the two carriages

            Δ (Pₓ / Py) =?

 Let's start by finding the momentum of each vehicle

car X

        Pₓ = m vₓ

        Pₓ = 2.34 2.5

        Pₓ = 5.85 kg m

car Y

        Py = 2,561 3.2

        Py = 8,195 kgm

How do we calculate the absolute uncertainty at the two moments?

          ΔPₓ = m Δv + v Δm

          ΔPₓ = 2.34 0.01 + 2.561 0.01

          ΔPₓ = 0.05 kg m

         ΔP_{y} = m Δv + v Δm

         ΔP_{y} = 2,561 0.01+ 3.2 0.001

         ΔP_{y} = 0.03 kg m

now we have the uncertainty of each moment

          P = Pₓ / P_{y}

          ΔP = ΔPₓ/P_{y} + Pₓ ΔP_{y} / P_{y}²

          ΔP = 8,195 0.05 + 5.85 0.03 / 8,195²

          ΔP = 0.006 + 0.0026

          ΔP = 0.009 kg m

The result is

           P = 14,045 ± 0.039 = (14,045 ± 0.03 )  k gm/s

7 0
3 years ago
A medical treatment where the individual breathes in pure oxygen while in a pressurized room or through a tube. This increased p
Leto [7]
Hyperbaric Oxygen Therapy (HBOT) is a medical treatment where the individual breathes in pure oxygen while in a pressurized room or through a tube. The HBOT treatment includes breathing 100% oxygen while under increased atmospheric pressure. It is used <span>for decompression sickness by scuba divers.</span>
5 0
3 years ago
If 2 electrically charged objects repel one another , which of the statements could be true, one object has more electrons, the
fiasKO [112]
Both objects have the same electrical charge. Opposite charges attract. And if they were neutral they would not do anything.
6 0
3 years ago
Read 2 more answers
Other questions:
  • John traveled East at 10 m/s for ten
    15·1 answer
  • The word centripeta/means "<br> -seeking."<br> Answer here
    9·1 answer
  • A skateboarder with mass ms = 54 kg is standing at the top of a ramp which is hy = 3.3 m above the ground. The skateboarder then
    14·1 answer
  • Answer this for me please and thank you
    8·1 answer
  • Speed is the rate at which what happens?
    12·1 answer
  • Stars located near _____ appears to move in circles when viewed from earth
    11·1 answer
  • What is the entropy of a closed system in which 28 distinguishable grains of sand are distributed among 1000 distinguishable equ
    10·1 answer
  • PLZ HELP NO SNEAKY LINK OR I WILL REPORT U OR NON ANSWERS
    9·1 answer
  • The distance from Abdullah's house to his school is 2.4km. Abdulla takes 0.6h to go to school on his cycle but takes only 0.4h t
    7·1 answer
  • Explain on any two modifications that you would expect to use for the thermos flask which would enable it to be handier/helpful.
    6·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!