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Sladkaya [172]
4 years ago
12

Gasoline comes from petroleum, which is made from ancient living things. Petroleum, therefore, contains a type of _____ energy.

Physics
2 answers:
Maurinko [17]4 years ago
8 0

Chemical potential energy is the correct answer.

Virty [35]4 years ago
4 0
D chemical potential I think
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When current flows through this wire, what forms around the wire?(20 points)
Korvikt [17]
The answer your looking for is magnetic field
3 0
3 years ago
Read 2 more answers
Someone help please.....
Westkost [7]

Answer:

0.0928km/min (4dp)

Explanation:

To find the jogger's speed in km per minute, we just need to divide the number of km jogged by the time in minutes it took to jog that distance. This will give us the distance they jogged every minute which is their speed.

4km in 32 minutes:

4/32 = 0.125km/min

2km in 22 minutes:

2/22 = 0.091 (3dp)km/min

1km in 16 minutes:

0.0625km/min

Now to find the average speed of these 3 speeds, we just add them all together and divide by how many values there are (3 values).

Average (mean)  = \frac{0.125+0.091+0.0625}{3}

Average = 0.2785/3

Average speed of jogger = 0.0928 (4dp) km/min

Hope this helped!

8 0
3 years ago
A barrel 1 m tall and 60 cm in diameter is filled to the top with water. What is the pressure it exerts on the floor beneath it?
allsm [11]

Answer:

The pressure on the ground is about 9779.5 Pascal.

The pressure can be reduced by distributing the weight over a larger area using, for example, a thin plate with an area larger than the circular area of the barrel's bottom side.  See more details further below.

Explanation:

Start with the formula for pressure

(pressure P) = (Force F) / (Area A)

In order to determine the pressure the barrel exerts on the floor area, we need the calculate the its weight first

F_g = m \cdot g

where m is the mass of the barrel and g the gravitational acceleration. We can estimate this mass using the volume of a cylinder with radius 30 cm and height 1m, the density of the water, and the assumption that the container mass is negligible:

V = h\pi r^2=1m \cdot \pi\cdot 0.3^2 m^2\approx 0.283m^3

The density of water is 997 kg/m^3, so the mass of the barrel is:

m = V\cdot \rho = 0.283 m^3 \cdot 997 \frac{kg}{m^3}= 282.151kg

and so the weight is

F_g = 282.151kg\cdot 9.8\frac{m}{s^2}=2765.08N

and so the pressure is

P = \frac{F}{A} = \frac{F}{\pi r^2}= \frac{2765.08N}{\pi \cdot 0.3^2 m^2}\approx 9779.5 Pa

This answers the first part of the question.

The second part of the question asks for ways to reduce the above pressure without changing the amount of water. Since the pressure is directly proportional to the weight (determined by the water) and indirectly proportional to the area, changing the area offers itself here. Specifically, we could insert a thin plate (of negligible additional weight) to spread the weight of the barrel over a larger area. Alternatively, the barrel could be reshaped (if this is allowed) into one with a larger diameter (and smaller height), which would achieve a reduction of the pressure.  

7 0
3 years ago
A hammer thrower accelerates the hammer (mass = 7.90 kg ) from rest within four full turns (revolutions) and releases it at a sp
Dmitriy789 [7]

Answer: 1) a=5.98 rad/sec² 2) a tan= 8.97 m/s² 3) a rad= 450.7 m/s²

4) F= 3,560.5 N 5) theta = 180º

Explanation:

1) By definition, angular acceleration is equal to the change in angular velocity over time.

Assuming an constant angular acceleration, we can use one of the equivalent kinematic equations for circular movement, as follows:

ωf² - ω₀² = 2. Δθ.γ

and we know also that ω = v/r = 26.0 m/s / 1.50 m = 17.3 rad/s

As the hammer thrower accelerated from rest, ω₀ = 0, so replacing by the values, we get the angular acceleration, γ, as follows:

γ = ωf² / 2. Δθ = (17.3)² rad²/s² / 2. 8 π rad = 5.98 rad/s².

2) Tangential acceleration, has the same relationship with radius that angular velocity, so we can write the following:

at = γ . r = 5.98 rad/sec². 1.50 m = 8.97 m/s²

3) The centripetal acceleration, by definition, is the change in direction of the linear velocity vector, over time, is always directed towards the center of the circle, and her magnitude is as follows:

ac = v² / r

Just before release, the velocity has a magnitude of 26.0 m/s, so ac is as follows:

ac = (26.0)² m²/s² / 1.50 m = 450.7 m/s²

4) Ignoring gravity, the only force acting on the hammer, is the one exerted by the thrower, and this force is just the centripetal force, which is the product of the hammer mass times the centripetal acceleration, as follows:

Fc = m . ac = 7.9 Kg. 450. 7 m/s² = 3,560.5 N

5) Ignoring gravity, as the force exerted by the thrower is always along the radius of the circle, towards the centre, if we represent the radius as a vector with origin in the center, the force is always anti-parallel to it, so the angle of the force with respect to the radius of the circular motion is 180°.

7 0
3 years ago
PLZ HELP ITS A TIMED TEST!!!!!!!!!!!!!!!!
sergij07 [2.7K]
Image #3 good luck!!!!!!!!!!!
7 0
3 years ago
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