Answer:
Explanation:
given,
diameter of merry - go - round = 2.40 m
moment of inertia = I = 356 kg∙m²
speed of the merry- go-round = 1.80 rad/s
mass of child = 25 kg
initial angular momentum of the system
final angular momentum of the system
from conservation of angular momentum
Answer:
The formula is dimensionally correct.
Explanation:
Given
Required
Prove its correctness
Write out the dimension of each:
--- displacement
--- velocity * time
--- acceleration * square of time
The expression becomes:
Apply law of indices
Both sides of the equation are equal
The first thing you should know is that the friction force is equal to the coefficient of friction due to normal force.
Therefore, clearing the normal force we have:
The friction is 565N.
(565 / 0.8) = 706.25N. weight.
Answer:
A 1.5 metres per second squared B 0 C 6 0.5
b) 9m
Explanation:
a= v-a/t
a= acceleration measured in metres per second squared
v= final speed measured in metres per second
u= initial speed measured in metres per second
t= time measured in second
A
a=v-a/t
a= 3-0/2
a= 1.5 metres per second squared
Distance in a velocity time graph = area under
To calculate the distance in the first 4 seconds
You divide the graph into triangles and rectangles
Area A (triangle )= 1/2 × base × height
=1÷2 ×2×3
= 3m
Area B (rectangle)= L×B
=2×3
=6m
Area A + Area B= 3+6
= 9m
Answer:
V = ?
C = 3 × 10^8
wavelength = 2.10 × 10^-7
wavelength = C/V
V = C/wavelength
V = 3 × 10^8/2.10 × 10^-7
V = 1.43 × 10^ 15
