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DaniilM [7]
3 years ago
8

What type of thermodynamic system is best to use to describe an operating automobile engine? A) Open O B) Dilated O C) Isolated

( D) Closed Save
Physics
1 answer:
densk [106]3 years ago
5 0

Answer:

The answer to the given question from multiple options below is

option (a)

Explanation:

An operating automobile engine is an open system as it allows the exchange of matter and energy in between the system and its surrounding.

The other options do not comply, for example, as in isolated system no matter and energy is not exchanged and the other two options also do not favor atleast one of the two exchanges.

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spectroscope or a spectrometer is an instrument which is used for separating the components of light, which have different wavel
ohaa [14]

Answer:

The answer is B

Explanation:

The line spectrum shows distinct light different energies and wavelengths

7 0
2 years ago
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Which of the following hypotheses is both falsifiable and testable?
rosijanka [135]
B. If all plants are watered at least once a day then they will all grow at least 1 cm a day.

All plants grow at different rates.

Hope this helps! XD
5 0
3 years ago
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An electron is accelrated by a unifor electric field (1000v/m) pointing vertically upward. Use energy methods to get the magnitu
ExtremeBDS [4]

Explanation:

In the given situation two forces are working. These are:

1) Electric force (acting in the downward direction) = qE

2) weight (acting in the downward direction) = mg

Therefore, work done by all the forces = change in kinetic energy

Hence, qE \times S + mg \times S = 0.5 \times mv^{2}

     1.6 \times 10^{-19} \times 1000 + 9.1 \times 10^{-31} \times 9.8 \times (\frac{0.10}{100}) = 0.5 \times 9.1 \times 10^{-31} \times v^{2}

It is known that the weight of electron is far less compared to electric force. Therefore, we can neglect the weight  and the above equation will be as follows.

   (1.6 \times 10^{-19} \times 1000) \times (\frac{0.10}{100}) = 0.5 \times 9.1 \times 10^{-31} \times v^{2
}

         v = sqrt{\frac{1.6 \times 10^{-19}}{(0.5 \times 9.1 \times 10^{-31})}

           = 592999 m/s

Since, the electron is travelling downwards it means that it looses the potential energy.

8 0
2 years ago
At a certain elevation, the pilot of a balloon has a mass of 120 lb and a weight of 119 lbf. What is the local acceleration of g
Strike441 [17]

Answer:

31.905 ft/s²

Explanation:

Given that

Mass of the pilot, m = 120 lb

Weight of the pilot, w = 119 lbf

Acceleration due to gravity, g = 32.05 ft/s²

Local acceleration of gravity of found by using the relation

Weight in lbf = Mass in lb * (local acceleration/32.174 lbft/s²)

119 = 120 * a/32. 174

119 * 32.174 = 120a

a = 3828.706 / 120

a = 31.905 ft/s²

Therefore, the local acceleration due to gravity at that elevation is 31.905 ft/s²

3 0
3 years ago
If youre reading this goodluck in school homie <3
bazaltina [42]
I needed this ! Thanks a lot
7 0
3 years ago
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