During which month is the bacteria population just under 1 million?

In a tug of war, two teams exerts a force of 30 N each. What is the net force acting on the rope?

Arte-miy333 [17]

The force exerted by each team is 30 N. The forces are in the direction opposite to each other.

Force exerted by team 1, $F_{1}=30 N$

Force exerted by team 2, $F_{2}=-30 N$

Net force, $F=F_{1} +F_{2}$

$=30+(-30)=0$

Therefore, net force on the rope is 0 N.

4 0

3 years ago

Need help ASAP shoving brainlest plsssss

seraphim [82]

The answer for this would be B!!

3 0

3 years ago

How can we alter the pitch of guitar

zhenek [66]

Answer:

Tuning the keys.

Explanation:

"Guitar strings are tuned (tightened and loosened) using their tuning keys. Applying too much tension to a string tightly can raise it to the pitch of the next note, while loosening it can easily lower it the same amount. Increasing the tension raises the pitch. The length of a string is also important."

I hope this answers your question! Have a good night!

4 0

3 years ago

Read 2 more answers

Rodney is trying out one of Santa's new games that consists of three pieces that blow apart if the wrong key is inserted into th

ch4aika [34]

Answer:

The third piece moves at 6.36 m/s at an angle of 65° below the horizon

Explanation:

Linear Momentum

It's a physical magnitude that measures the product of the velocity by the mass of a moving object. In a system where no external forces are acting, the total momentum remains unchanged regardless of the interactions between the objects in the system.

If the velocity of an object of mass m is $\vec v$ , the linear momentum is computed by

$\displaystyle \vec{P}=m.\vec{v}$

a)

The momentum of the board before the explosion is

$\displaystyle \vec{P}_{t1}=m_t\ \vec{v}_o$

Since the board was initially at rest

$\displaystyle \vec{P}_{t1}=$

After the explosion, 3 pieces are propelled in different directions and velocities, and the total momentum is

$\displaystyle \vec{P}_{t2}=m_1\ \vec{v}_1\ +\ m_2\ \vec{v}_2+m_3\ \vec{v}_3$

The first piece of 2 kg moves at 10 m/s in a 60° direction

$\displaystyle \vec{v}_1=(10\ m/s,60^o)$

We find the components of that velocity

$\displaystyle \vec{v}_1=$

$\displaystyle \vec{v}_1=m/s$

The second piece of 1.2 kg goes at 15 m/s in a 180° direction

$\displaystyle \vec{v}_2=(15,180^o)$

Its components are computed

$\displaystyle \vec{v}_2=(15\ cos180^o,15\ sin180^o)$

$\displaystyle \vec{v}_2=(-15,0)\ m/s$

The total momentum becomes

$\displaystyle P_{t2}=2+1.2+m_3\ \vec{v}_3$

Operating

$\displaystyle P_{t2}=++m_3\ \vec{v}_3$

Knowing the total momentum equals the initial momentum

$\displaystyle P_{t2}=+m_3\ \vec{v}_3=0$

Rearranging

$\displaystyle m_3\ \vec{v}_3=$

Calculating

$\displaystyle m_3\ \vec{v}_3=$

This is the momentum of the third piece

b)

From the above equation, we solve for $\vec v_3$ :

$\displaystyle \vec{v}_3=\frac{1}{3}$

$\displaystyle \vec{v}_3=m/s$

The magnitude of the velocity is

$\displaystyle \vec{v}_3|=\sqrt{2.67^2+(-5.77)^2}=6.36$

And the angle is

$\displaystyle tan\theta =\frac{-5.77}{2.67}=-2.161$

$\displaystyle \theta =-65.17^o$

The third piece moves at 6.36 m/s at an angle of 65° below the horizon

5 0

4 years ago

Calculate the Δy for the maximum height of the tennis ball

Slav-nsk [51]

Δy for the maximum height of the tennis ball will be 0 as the angle of projection of the tennis ball is 90°.

The x- and y-components of motion during flight can be addressed independently of one another. The y-component of velocity is briefly zero at maximum height. A projectile is an object with an initial velocity that is affected by gravity. The object's greatest height is the highest vertical position along its journey.

When you fire a projectile at an angle from the horizontal, the projectile's initial velocity has both a vertical and a horizontal component. Gravity influences the projectile's vertical motion. This indicates that the vertical component of the starting speed will be zero at maximum height. The horizontal movement of the object in the projectile determines the projectile's range, which is determined by the object's starting velocity.

Learn more about y-component here:

brainly.com/question/24327456

#SPJ1

5 0

1 year ago