Answer:
Range = 22.61 m
Explanation:
We can use the formula for the Range in flat ground, given by:
which for our case renders:
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1 answer:
Answer:
Magnitude of static friction force is 70 sin40° = 44.99 N.
No, it is not necessary that it is maximum static friction.
Normal force is equal to 70 cos40° = 53.62 N.
Explanation:
We apply newton law of moton equation along the plane and perpendicular to plane;
Along the plane,
70 sin 40° = ---------------(1)
70 cos 40° = N --------------(2)
= μN -----------------(3)
So, it depends on the value of μ that the friction is maximum or not .
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Answer:
θ = 19.66°
Explanation:
To determine the angle that the rope makes with the vertical for the two people, you first take into account the potential energy of the first person before he swings on the rope:
h: distance to the ground
g: gravitational acceleration = 9.8m/s^2
m: mass of the first person = 55 kg
In the image attache below you can notice that the height h is:
Then, the potential energy is:
When the first person picks up the second person (when the rope is exactly vertical), all the potential energy becomes kinetic energy. Next, when both people reaches the maximum height h' the energy must be equal to the initial potential energy of the first person:
From the previous equation you can get h':
Finally, you obtain the angle between the rope at the height h,' and the vertical, by calculating the following:
hence, the angle between the rope and the vertical, when the two people are in the rope is 19.66°
Answer:
d = 13.7 m
Explanation:
When block is moving upwards along the inclined plane
then the block is decelerated due to gravity as well as due to friction and speed of the block by which it is projected upwards is given
deceleration caused to the block due to net force opposite to the motion is given as
since block is sliding on the inclined plane
so here we can say that the coefficient of the friction must be kinetic friction here
now for finding the distance upto which it will stop is given as