Answer:
Magnitude of static friction force is 70 sin40° = 44.99 N.
No, it is not necessary that it is maximum static friction.
Normal force is equal to 70 cos40° = 53.62 N.
Explanation:
We apply newton law of moton equation along the plane and perpendicular to plane;
Along the plane,
70 sin 40° = ---------------(1)
70 cos 40° = N --------------(2)
= μN -----------------(3)
So, it depends on the value of μ that the friction is maximum or not .
We are given volume of gasoline = 15.58 L and
Density = 0.74 g/mL.
Density is given in grams(g) per milliliter (mL). So, we need to convert given volume in mL also.
We know, 1 litre = 1000 milliliters
Therefore, 15.58 L = 15.58 * 1000 mL = 15580 mL
We could rewrite,
Volume of gasoline = 15580 mL.
Formula for density is..
Density (ρ)=
Plugging values in formula,
0.74 g/mL =
Muliplying both sides by 15580.
11529.2g = mass.
Therefore, 11529.2g grams does 15.58 L of gasoline weigh.
Answer:
Approximately . (Assuming that
, and that the tabletop is level.)
Explanation:
Weight of the book:
.
If the tabletop is level, the normal force on the book will be equal (in magnitude) to weight of the book. Hence, .
As a side note, the and
on this book are not equal- these two forces are equal in size but point in the opposite directions.
When the book is moving, the friction on it will be equal to
That is:
.
Friction acts in the opposite direction of the object's motion. The friction here should act in the opposite direction of that applied force. The net force on the book shall be:
.
Apply Newton's Second Law to find the acceleration of this book:
.