All categories

3 years ago

A metal container with the oil weigh

Physics

1 answer:

MA_775_DIABLO [31]3 years ago

7 0

Answer:

16 kg

Explanation:

M - container

m - oil mass

by definition of density ,

relative density is the ratio of the density of a substance to the density of water.

relative density = density/ density of water

density of oil = 1.2*1000 kgm⁻³ = 1200 kgm⁻³

1 Litre =10⁻³ m³

oil volume = 80 *10⁻³ m³

mass of oil = density * volume

= 1200*80*10⁻³

= 96 kg

Mass of container + mass of oil =112

mass of container = 112 - 96

= 16 kg

You might be interested in

Four boxes of increasing size and weight must be pushed up a ramp. To push the boxes at the same speed, what must you do?

kari74 [83]

Have the heaviest in the back, progressively to the lightest in the front, going first.

5 0

4 years ago

Read 2 more answers

a raft of dimensions 2m wide by 3m long by .5m thick is floating in a pond if one fourth of the raf is submerged find the densit

11111nata11111 [884]

Answer:

250 kg/m3

Explanation:

The total volume of the raft is length times width times height

V = lwh = 2 * 3 * 0.5 = 3 m cubed

The volume of the raft that is submerged in water is 1/4 of total volume

3 /4 = 0.75 m cubed

Let water density = 1000 kg/m cubed and g = 10 m/s2

The buoyant force is equal to the weight of water displaced by the raft

F = 0.75 * 1000 * 10 = 7500 N

This force is balanced by the raft weight, so the weight of the raft is also 7500N

Mass of raft is 7500 / g = 7500 / 10 = 750 kg

Raft density is mass divided by volume = 750 / 3 = 250 kg/m3

8 0

3 years ago

proton is accelerated to a speed of 0.93c, what is the 1. A proton has a mass of 1.673 x 10-27 kg. If the proton is accelerated

coldgirl [10]

Answer : The correct option is, (B) $1.3\times 10^{-18}kg.m/s$

Explanation : Given,

Mass of proton = $1.673\times 10^{-27}kg$

Speed of proton = 0.93 c

Formula used for relativistic momentum of the proton is:

$p=\frac{m_ov}{\sqrt{1-\frac{v^2}{c^2}}}$

where,

p = relativistic momentum of the proton

$m_o$ = mass of proton

v = speed of proton

c = speed of light = $3\times 10^8m/s$

Now put all the given values in the above formula, we get:

$p=\frac{(1.673\times 10^{-27}kg)\times (0.93c)}{\sqrt{1-\frac{(0.93c)^2}{c^2}}}$

$p=\frac{(1.55589\times 10^{-27}c)}{0.367}$

$p=\frac{(1.55589\times 10^{-27})\times (3\times 10^8)}{0.367}$

$p=1.272\times 10^{-18}kg.m/s\approx 1.3\times 10^{-18}kg.m/s$

Therefore, the relativistic momentum of the proton is, $1.3\times 10^{-18}kg.m/s$

5 0

3 years ago

Suppose you stand on the rim of a space station. If the radius of the station is 12,000

ale4655 [162]

Answer:

circle

Explanation:

because Earth is not oblong

8 0

3 years ago

A light ray is incident on a plane surface separating two transparent media of refractive indices of 1.65 and 1.35. If the incid

Vesna [10]

Explanation:

Given

Refractive Index $(n_1)=1.65$

$n_2=1.35$

angle of incident $=35 ^{\circ}$

Light originates in the medium of higher refractive index

Let $\theta _1$ and $\theta _2$ be the incident and refraction angles respectively thus according to snell's law

$n_1sin\theta _1=n_2sin\theta _2$

$1.65\times sin35=1.35\times sin\theta _2$

$sin\theta _2=0.701$

$\theta _2=44.507^{\circ}$

(b)Ray originates from lighter medium

$1.35\times sin35=1.65\times sin\theta _2'$

$sin\theta _2'=0.469$

$\theta _2'=27.96\approx 28^{\circ}$

8 0

4 years ago