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cupoosta [38]
3 years ago
13

3. Sailors use a capstan (shown below) to raise and lower the anchor. It takes two sailors located 1 meter from the center to tu

rn the capstan.
How far from the center would one sailor have to be to turn the capstan by himself?
A 1 meter
B. 2 meters
C.3 meters
D. Both B and C would work

Physics
1 answer:
mr_godi [17]3 years ago
4 0

Answer:

B. 2 meters.

Explanation:

To rotate the capstan a certain amount of torque is required, and if each sailor applies a force F at a distance D from the center, then for two sailors the total torque will be

\tau = 2FD\\;

therefore,  for one sailor to apply the same torque it must be that the torque \tau_2 he applies must be equal to the torque that the two sailors applied:

FD_2 =2FD

which gives

D_2 = 2D.

and since D = 1\:meter,

\boxed{D_2 = 2\: meters}

which is choice B.

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amping equipment weighing 6.0 kN is pulled across a frozen lake by means of ahorizontal rope. The coecient of kinetic friction i
Harman [31]

Answer:

Work done = 422.45 kJ

Explanation:

given,                                  

weight of equipment = 6 kN      

coefficient of kinetic friction = 0.05          

distance up to which it is pulled = 1000 m

constant acceleration = 0.2 m/s²                    

Work done by the camper = ?                

actual acceleration acting a'      

m a = m a' - μ mg            

a' = a + μ g                      

a' = 0.2 + 0.05 x 9.8                

a' = 0.69 m/s²                              

Work done = Force x distance

F = m a'                                                            

F = \dfrac{6000}{9.8} \times 0.69

F = 422.44897 N                            

Work done = F x d                          

Work done = 422.44897 x 1000

Work done = 422449 J                  

Work done = 422.45 kJ            

4 0
3 years ago
What does Force Means​
zubka84 [21]

Answer:

strength or energy as an attribute of physical action or movement.

Explanation:

coercion or compulsion, especially with the use or threat of violence.

this is from google

3 0
3 years ago
Read 2 more answers
PLEASE HELP ME What does a moving charge experience when it is near a magnetic field? static friction gravity a stationary charg
attashe74 [19]

<u><em>A moving charge experiences a force as it moves close to a magnetic field present in a region.</em></u>

Explanation:

A charged particle when moves near a magnetic field is forced to move in a circular path. If there is a straight moving charged particle enters the region of the magnetic field, it's path is changed from straight path to the curved path.

The motion of the charged path inside or near the magnetic field will be a circular path and this circular path is due to the force experienced by the charged particle in the magnetic field.

The force experienced by the a charged particle as it moves near the magnetic field is termed as the Lorentz force. The expression for the Lorentz force experienced by the charged particle in the magnetic field is given by:

\boxed{F_m=Q(\overrightarrow{v}\times\overrightarrow{B})}

Here, F_m is the magnetic force, Q is the amount of charge, \overrightarrow{v} is the velocity vector and \overrightarrow{B} is the magnetic field intensity in the region.

Thus, <u><em>A moving charge experiences a force as it moves close to a magnetic field present in a region.</em></u>

Learn More:

1. Which one is true for the electromagnetic spectrum brainly.com/question/1619496

2. What is the current in resistor R2 brainly.com/question/3051098

3. Average current denisty of a linear wire brainly.com/question/10597501

Answer Details:

Grade: High School

Subject: Physics

Chapter: Electromagnetism

Keywords:

moving, charge, straight, circular, path, magnetic, field, amount, force, velocity, intensity, Lorentz, expression, stationary.

6 0
3 years ago
An elevator is accelerating upward at a rate of 3.6 m/s2. a block of mass 24 kg hangs by a low-mass rope from the ceiling, and a
kozerog [31]
The answer:

<span>When the elevator accelerates upward at a rate of 3.6 m/s², the value of the acceleration becomes

</span>A=g+3.6=13.4 m/s²
and by using the newton's law, F=mass x A, we have 
T1= (24 + 90 )x 13.4= 1527.6 N, where T1 is the <span>Tension in upper rope
</span> and 
T2= ( 90 )x 13.4= 1206N, where T2 is the Tension in lower rope

When the elevator accelerates downward at a rate of 3.6 m/s², the value of the acceleration becomes
A=9.8 - 3.6 = 6.2 m/s²

T1= (24 + 90 )x 6.2= 706.8 N, where T1 is the Tension in upper rope
 and 
T2= ( 90 )x 6.2= 558N, where T2 is the Tension in lower rope


5 0
3 years ago
Please help meeeee :((((((((((​
NeX [460]

Answer:

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Explanation:

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