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Paha777 [63]
3 years ago
8

Subtract 4x-5 from 2/5 + 7 PLEASE HELP I HAVE 4 MINUTES

Mathematics
1 answer:
Dafna11 [192]3 years ago
4 0
The answer would be 4x-(62/5)

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Pls help a brother out!
Leviafan [203]

Answer:

12 maybe the ANSWER.

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4 years ago
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A company manager for a tire manufacturer is in charge of making sure there is the least amount of defective tires. If the tire
Anestetic [448]

Answer:

0.347% of the total tires will be rejected as underweight.

Step-by-step explanation:

For a standard normal distribution, (with mean 0 and standard deviation 1), the lower and upper quartiles are located at -0.67448 and +0.67448 respectively. Thus the interquartile range (IQR) is 1.34896.

And the manager decides to reject a tire as underweight if it falls more than 1.5 interquartile ranges below the lower quartile of the specified shipment of tires.

1.5 of the Interquartile range = 1.5 × 1.34896 = 2.02344

1.5 of the interquartile range below the lower quartile = (lower quartile) - (1.5 of Interquartile range) = -0.67448 - 2.02344 = -2.69792

The proportion of tires that will fall 1.5 of the interquartile range below the lower quartile = P(x < -2.69792) ≈ P(x < -2.70)

Using data from the normal distribution table

P(x < -2.70) = 0.00347 = 0.347% of the total tires will be rejected as underweight

Hope this Helps!!!

6 0
4 years ago
CS Algebra
CaHeK987 [17]

Answer:

Hope this helps :)

Step-by-step explanation:

8(x - 2) = 2x + 8

y+9 = -2(y + 1)

value of x in 8(x - 2) = 2x + 8

x=4

substitue

y+9=−2(y+1)

value of y y+9=−2(y+1)

y= - 11/3 or 3.66...

x=4

y=4 (I rounded 3.66)

4 0
3 years ago
Use long division to find the quotient below (30x^3+4x^2-150) / (6x-10)
Anni [7]

Answer:

The answer is

A.5x^2+9x+15

Step-by-step explanation:

kindly find attached the solving for proper understanding and solution flow.

Given Data

the divisor=  6x-10

dividend= 30x^3+4x^2-150

firstly for us to perform the division we need to re write the dividend and include the missing coefficient of x

dividend =30x^3+4x^2+0x-150

3 0
4 years ago
- A picture frame is 12 inches long and 9 inches wide. In inches, what is the diagonal length of
sp2606 [1]
I would say 15 inches
7 0
3 years ago
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