We can solve this problem when we use the conditions of a gas at standard temperature and pressure. It has been established that at STP where the temperature is 0 degrees Celsius and the pressure is 101.325 kPa, the volume of 1 mole of gas is 22.4 L. We will use this data for the calculations.
68.5 L ( 1 mol O2 / 22.4 L O2 ) = 3.06 mol O2
Answer:
Explanation:
Assume the chemical equation:
- Zn(s) + 2HCl(aq) → ZnCl₂(aq) + H₂(g)
<u>1. Convert 112 liters of hydrogen gas at STP to number of moles.</u>
You can use the molar volume of a gas at STP equal to approximately 22.4 liters.
<u>2. Use the theoretical mole ratio</u>
From the balanced chemical equation, 1 mol of Zn produced 1 mol of H₂(g).
Thus, the mole ratio is 1 : 1, and 5 moles of Zn are needed to produce 5 moles of H₂(g).
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<u>3. Convert 5 moles of Zn to mass in grams</u>
- mass in grams = number of moles × atomic mass
- mass = 5 mol × 65.39g/mol = 326.95 g
Round to 3 significant figures: 327g
The theoretical molar yield of lead (II) chloride will be 9 moles.
<h3>Stoichiometric calculation</h3>
First, we need to look at the equation of the reaction:
From the equation, the 1 mole of Pb2+ ion requires 2 moles of Cl- ion in order to produce 1 mole of lead (II) chloride.
Thus, with 18 moles Cl- ions, 9 moles of Pb2+ would be needed, instead of 12 moles. Pb2+ is simply in excess while Cl- can be said to be limiting.
Therefore, Cl- will determine how much of lead (II) chloride that will be produced. The ratio is 2 moles of Cl- to 1 mole of lead (II) chloride.
With 18 moles Cl-, 9 moles of lead (II) chloride will, thus, be produced.
More on mole ratios can be found here: brainly.com/question/14425689
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