Answer:
w = -531 kJ
1. Work was done by the system.
Explanation:
Step 1: Given data
- Heat gained by the system (q): 687 kJ (By convention, when the system absorbs heat, q > 0).
- Change in the internal energy of the system (ΔU°): 156 kJ
Step 2: Calculate the work done (w)
We will use the following expression.
ΔU° = q + w
w = ΔU° - q
w = 156 kJ - 687 kJ
w = -531 kJ
By convention, when w < 0, work is done by the system on the surroundings.
Answer:
[K₂CrO₄] → 8.1×10⁻⁵ M
Explanation:
First of all, you may know that if you dilute, molarity must decrease.
In the first solution we need to calculate the mmoles:
M = mmol/mL
mL . M = mmol
0.0027 mmol/mL . 3mL = 0.0081 mmoles
These mmoles of potassium chromate are in 3 mL but, it stays in 100 mL too.
New molarity is:
0.0081 mmoles / 100mL = 8.1×10⁻⁵ M
It dissolves I think I know I am expert and. Ute
Answer:
The answer to your question is 6.0 moles of O₂
Explanation:
Data
2KClO₃ ⇒ 2KCl + 3O₂
moles of O₂ = ?
moles of KCl = 4
Process
To find the number of moles of O₂, use proportions and cross multiplication.
Use the coefficients of the balanced equation.
2 moles of KCl ----------------- 3 moles of O₂
4 moles of KCl ----------------- x
x = (4 x 3) / 2
-Simplification
x = 12/2
-Result
x = 6 moles of O₂
-Conclusion
When 4,0 moles of KCl are produced, 6.0 moles of O₂ will be produced.
