Answer:
19 g
Explanation:
Data Given:
Sodium Chloride (table salt) = 50 g
Amount of sodium (Na) = ?
Solution:
Molecular weight calculation:
NaCl = 23 + 35.5
NaCl = 58.5 g/mol
Mass contributed by Sodium = 23 g
calculate the mole percent composition of sodium (Na) in sodium Chloride.
Since the percentage of compound is 100
So,
Percent of sodium (Na) = 23 / 58.5 x 100
Percent of sodium (Na) = 39.3 %
It means that for ever gram of sodium chloride there is 0.393 g of Na is present.
So,
for the 50 grams of table salt (NaCl) the mass of Na will be
mass of sodium (Na) = 0.393 x 50 g
mass of sodium (Na) = 19 g
Hey there!
The pathway will resemble a hill , The minimum amount of energy the reagents need to make the complex activated, is the activation energy , The difference in heights of the products and reactants will be equivalent to the difference in energies.:
ΔH = ( -1,023 kj ) - ( - 935,3 kj )
ΔH = -87.7 Kj
1 ounces ----------- 29.5735 mL
5 ounces ----------- ??
5 x 29.5735 / 1 => 147.868 mL
hope this helps!
This is only true for the titration of a strong acid with a strong base or vice versa. At the equivalence point of the titration of a weak base with a strong acid the pH is less than 7.00 and at the equivalence point of the titration of a weak acid with a strong base the pH is greater than 7.00.
<span> strictly speaking, a molecule has at least two atoms. ... Atoms with full valence electron shells are stable. Full Text[ edit ] The noble gases are a group of chemical elements that make up Group 18 on the periodic table.</span>
