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MariettaO [177]
3 years ago
9

I think that when the temperature decreases, the pressure will __________. When things are cooled,________________..

Chemistry
1 answer:
anygoal [31]3 years ago
6 0

Answer:

See below ~

Explanation:

From The Ideal Gas Equation,

  • P ∝ T

Therefore,

I think that when the temperature decreases, the pressure will <u>decrease</u>. When things are cooled, <u>pressure decreases</u>.

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List the symbols for the noble gases
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Answer:here:

Explanation:helium (He), neon (Ne), argon (Ar), krypton (Kr), xenon (Xe), radon (Rn), and oganesson (Og).

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2 years ago
Compared to the charge of a proton, the charge of all electron has
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<span>Answer: option (4) the same magnitude and the opposite sign.
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Justification:
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</span><span>1) Electrons are negative particles thar are around the nucleus of the atom (in regions called orbitals).
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2) Protons are positive particles that are inside the nuclus of the atom.
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<span>3) The nucleus of the atom has the same number of protons as electrons are in the orbitals of the atom.
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4) The atoms are neutral (neither positive nor negative) because there are the same number of electrons and protons and their charge are of the same magnitude but different sign: (+) + (-) = 0: positive + negative = neutral.</span>
6 0
3 years ago
Read 2 more answers
Write the formula for methionine (red = O , gray = C , blue = N , yellow = S , ivory = H ).
Arlecino [84]

Answer:

The molecular formula of methionine is C₅H₁₁NO₂S

7 0
2 years ago
If 135.7 J of heat are added to 54.0 g of water initially at 25.0 °C . What is the final temperature of the water?
german

Answer:

The final temperature of the water is 25.6 °C.

Explanation:

We have,

Heat added to water is 135.7 J

Mass, m = 54 g

Initial temperature was 25 °C

It is required to find the final temperature of the water. The heat added when temperature is increased is given in terms of specific heat capacity as :

Q=mc(T_f-T_i)

T_f is final temperature

c is specific heat capacity, for water, c=4.184\ J/g^{\circ} C

So,

T_f=\dfrac{Q}{mc}+T_i\\\\T_f=\dfrac{135.7}{54\times 4.184}+25\\\\T_f=25.6^{\circ} C

So, the final temperature of the water is 25.6 °C.

3 0
4 years ago
A 32.2 g iron rod, initially at 21.9 C, is submerged into an unknown mass of water at 63.5 C. in an insulated container. The fin
lorasvet [3.4K]

Answer : The mass of the water in two significant figures is, 3.0\times 10^1g

Explanation :

In this case the heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

where,

c_1 = specific heat of iron metal = 0.45J/g^oC

c_2 = specific heat of water = 4.18J/g^oC

m_1 = mass of iron metal = 32.3 g

m_2 = mass of water = ?

T_f = final temperature of mixture = 59.2^oC

T_1 = initial temperature of iron metal = 21.9^oC

T_2 = initial temperature of water = 63.5^oC

Now put all the given values in the above formula, we get

32.3g\times 0.45J/g^oC\times (59.2-21.9)^oC=-m_2\times 4.18J/g^oC\times (59.2-63.5)^oC

m_2=30.16g\approx 3.0\times 10^1g

Therefore, the mass of the water in two significant figures is, 3.0\times 10^1g

3 0
3 years ago
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