Question

Examine the forces acting on a car on a ramp. Select the forces or force components that need to be added together to calculate the net force in the x-direction. Check all that apply.
FN
–Ff
–Fg
Fg (cos 15°)
Fg (sin 15°)

Answer 1

The answer is -Ff & Fg(sin 15°)

Answer 2

Answer:

Frictional force, $-F_f$ and Weight, $F_g\ sin(15^0)$

Explanation:

The attached figure shows the free body diagram of a car placed at the ramp. The net forces acting the car :

1. Normal force

2. Weight, mg

3. Frictional force

But the forces acting on the car in x- direction or horizontal path are frictional force (which acts in opposite direction of the motion) and of its weight.

So, the correct options are :

• Frictional force, $-F_f$
• Weight, $F_g\ sin(15^0)$