Answer:
3 inches
Step-by-step explanation: An equilateral triangle means all 3 sides are the same length.
A square also have the same length for all 4 sides.
So each side of the square is 6cm, to find the perimeter you do 6*4=24.
then divide the square's perimeter by 3 since triangle have 3 sides. 24/3=8
so each side of the triangle will be 8cm
Answer:
C = 68.667°
a = 123.31 yd.
c = 114.90 yd.
Step-by-step explanation:
The missing image for the question is attached to this solution.
In the missing image, a triangle AB is given with angles A and B given to be 88° 35' and 22° 45' respectively
We are them told to find angle C and side a and c given that side b = 47.7 yd.
A = 88° 35' = 88° + (35/60)° = 88.583°
B = 22° 45' = 22° + (45/60)° = 22.75°
The sum of angles in a triangle = 180°
A + B + C = 180°
C = 180° - (A + B) = 180° - (88.583° + 22.75°) = 68.667°
The sine law is given as
(a/sin A) = (b/sin B) = (c/sin C)
Using the first two terms of the sine law
(a/sin A) = (b/sin B)
a = ?
A = 88.583°
b = 47.7 yd.
B = 22.75°
(a/sin 88.583°) = (47.7/sin 22.75°)
a = (47.7 × sin 88.583°) ÷ sin 22.75°
a = 123.31 yd.
Using the last two terms of the sine law
(b/sin B) = (c/sin C)
b = 47.7 yd.
B = 22.75°
c = ?
C = 68.667°
(47.7/sin 22.75°) = (c/sin 68.667°)
c = (47.7 × sin 68.667°) ÷ sin 22.75°
c = 114.90 yd.
Hope this Helps!!!
First pic ; they are complementary angles , so C !!
second pic ; both angles are supplementary angles !! as sum is 180° !!
Supposing, for the sake of illustration, that the mean is 31.2 and the std. dev. is 1.9.
This probability can be calculated by finding z-scores and their corresponding areas under the std. normal curve.
34 in - 31.2 in
The area under this curve to the left of z = -------------------- = 1.47 (for 34 in)
1.9
32 in - 31.2 in
and that to the left of 32 in is z = ---------------------- = 0.421
1.9
Know how to use a table of z-scores to find these two areas? If not, let me know and I'll go over that with you.
My TI-83 calculator provided the following result:
normalcdf(32, 34, 31.2, 1.9) = 0.267 (answer to this sample problem)
Answer:
Distance between the two planes after 1 hour = 410 miles
Step-by-step explanation:
Given - A plane leaves and flies due north at 280 miles per hour. At
the same time another plane takes off from the same airport
and flies due east at a speed of 300 miles per hour.
To find - What is the distance between the two planes after 1 hour ?
Proof -
Given that , Plane 1 flies due north at a speed of 280 miles per hour.
So,
Total distance traveled in 1 hour = 280 miles
Also,
Plane 2 flies due east at a speed of 300 miles per hour.
So,
Total distance traveled in 1 hour = 300 miles.
The diagram is as follows :
Now,
We have to find the distance after 1 hour i.e. AC
In Triangle ABC ,
By using Pythagoras theorem, we get
AC² = BC² + AB²
⇒AC² = (300)² + (280)²
⇒AC² = 90,000 + 78,400
⇒AC² = 168,400
⇒AC = √168,400
⇒AC = 410.366 ≈ 410
∴ we get
Distance between the two planes after 1 hour = 410 miles