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Semmy [17]
3 years ago
5

What is the equation of the following graph?

Mathematics
1 answer:
dangina [55]3 years ago
7 0

There are a couple of different ways you could do this, but I'll show the simpler way. We will use the formula

y=a(x-h)^2+k

along with the fact that the vertex has h and k coordinates of 1 and 4 respectively, and that a point on the graph is (3, 5). We could have used any point on the graph where there is a definite integer coordinate pair. We will fill in accordingly and solve for a.

5=a(3-1)^2+4 and

5 = 4a + 4. If we subtract 4 from both sides we get that a=\frac{1}{4}. Now we will fill in the formula and expand as needed:

y=\frac{1}{4}(x-1)^2+4 and

y=\frac{1}{4}(x^2-2x+1)+4. If we distribute the 1/4 in and then add the constants the final equation for that graph will be

y=\frac{1}{4}x^2-\frac{1}{2}x+\frac{17}{4}

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The graph of the function f(x) =4√x is shown.
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Step-by-step explanation:

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Determine whether each point lies on the graph of the equation.(a) 2x - y - 3 = 0 (a) (1, 2)Yes, the point is on the graph.No, t
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Answer:

a) (1, 2) not on the graph.

b) (1, -1) is on the graph.

Step-by-step explanation:

Given the equation of the line as:

2x - y - 3 = 0

The points given are

a) (1, 2)

To determine whether it is on the graph of the line or not.

To do so, we can do 2 things:

1. Draw the graph and plot the point on the graph to check whether it is on the graph or not.

2. To put the point in the given equation of the line, whether the equation is satisfied or not.

For method 1: Kindly refer to the attached image of the line and point plotted.

Method 2:

Let us put x=1, y=2 in the Left Hand Side (LHS) of equation.

2\times 1 - 2 - 3\\\Rightarrow -3 \neq 0 , RHS

(1, 2) Not on the graph.

(b) (1, -1)

For method 1: Kindly refer to the attached image of the line and point plotted.

Method 2:

Let us put x=1, y=-1 in the Left Hand Side (LHS) of equation.

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(1, -1) is on the graph.

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