27=3³ and 512=8³
(3x+8y)(9x²-24xy+84y²) are the two factors.
C is the answer.
4<span>(9<span>a2</span>−6a+1<span>)
Answer:</span></span>4<span><span><span>(3a−1)</span>2</span><span>4<span><span>(3a-1)</span>2</span></span></span>
Answer: a^2+b^2=c^2
Step-by-step explanation: (18^2=14^2+c^2)=324=196+c^2
324-196=128 and the square root of 128 is 8 radical 2 or in decimal form 11.31
I got D.
There's a few ways to solve it; I prefer using tables, but there are functions on a TI-84 that'll do it for you too. The logic here is, you have a standard normal distribution which means right away, the mean is 0 and the standard deviation is 1. This means you can use a Z table that helps you calculate the area beneath a normal curve for a range of values. Here, your two Z scores are -1.21 and .84. You might notice that this table doesn't account for negative values, but the cool thing about a normal distribution is that we can assume symmetry, so you can just look for 1.21 and call it good. The actual calculation here is:
1 - Z-score of 1.21 - Z-score .84 ... use the table or calculator
1 - .1131 - .2005 = .6864
Because this table calculates areas to the RIGHT of the mean, you have to play around with it a little to get the bit in the middle that your graph asks for. You subtract from 1 to make sure you're getting the area in the middle and not the area of the tails in this problem.