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SpyIntel [72]
3 years ago
7

Symbion pandora has a symbiotic relationship with the Norway lobster. True False

Physics
1 answer:
pashok25 [27]3 years ago
8 0
<em>The answer you are looking for is: </em>
<em><u>True</u>
Hope that helps!! </em>
<em>Have a wonderful day!! </em>
<em>If you ever need anything feel free to ask me!!</em>
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When students work in a chemistry lab, the location of which items would be the most important for each student to know?
irina [24]
The safety items such as eye washing station, fire blanket, and the class shower.
6 0
3 years ago
The density of gold is 19.3. G/cm(3). If a nugget of iron pyrite and nugget of gold each have a mass of 50 g, what can you concl
tangare [24]
The pyrite will be bigger, because its density is much lower.

I <em>do</em> know that the gold's volume will be 2.5906 (With a bunch more numbers after it)

50 divided by 19.3 = 2.5906
5 0
3 years ago
¿Qué nombre recibe un electrón que abandona el espacio interno del átomo dirigiéndose al exterior del átomo?
Alenkinab [10]

Answer:

i dont speack spanish sorry

Explanation: agian sorry

7 0
3 years ago
Water vapor enters the atmosphere through
Blizzard [7]

Answer:

Heat from the Sun causes water to evaporate from the surface of lakes and oceans. This turns the liquid water into water vapor in the atmosphere. Plants, too, help water get into the atmosphere through a process called transpiration! ... Water can also get into the atmosphere from snow and ice.

Most water vapor enters the atmosphere via evaporation and transpiration. Evaporation occurs when a single water molecule on a liquid water surface gains enough kinetic energy (often by solar radiation) to break the bond which holds the molecules together. Really Hopes this helps!

Explanation:

6 0
3 years ago
#1 Not sure where to start. This is for AP Physics!
yaroslaw [1]

First,

\rho=\dfrac mV

where \rho is density, m is mass, and V is volume. We can compute the volume of the roll:

2.7\,\dfrac{\mathrm g}{\mathrm{cm}^3}=\dfrac{1275\,\mathrm g}V

\implies V\approx472.22\,\mathrm{cm}^3\approx4.72\,\mathrm m^3

When the roll is unfurled, the aluminum will be a rectangular box (a very thin one), so its volume will be the product of the given area and its thickness x. Note that we're assuming the given area is not the actual total surface area of the aluminum box, but just the area of the largest face (i.e. the area of one side of the unrolled sheet of aluminum).

So we have

V=Ax

where A is the given area, so

4.72\,\mathrm m^3=\left(18.5\,\mathrm m^2\right)x

\implies x\approx0.255\,\mathrm m=255\,\mathrm{mm}

If we're taking significant digits into account, the volume we found would have been V=470\,\mathrm m^3, in turn making the thickness x=250\,\mathrm{mm}.

8 0
3 years ago
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