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son4ous [18]
1 year ago
10

a ball is projected horizontally from the top the building.One second later another ball is projected horizontally from the same

point with the same velocity.At what point In the motion will the balls be closest to each other?Will the first ball always be travelling faster than the second ball?What will be the time interval between them when the ball hits the ground?Can the horizontal projection velocity of the second ball be changed so that the balls arrive at the ground at the same time?
Physics
1 answer:
stellarik [79]1 year ago
8 0

The point In the motion that the balls will be closest to each other is as at the time as the second ball is thrown or lunched.

<h3>Will the first ball always be travelling faster than the second ball?</h3>

No, The two motions are said to be parallel to one another, so they that they both the same timing. Hence, the time it takes for both balls to be able to fall to the ground is said to be the same.

Yes, the both balls have the same speed because of  two balls are said to hit the ground, they are said to be done at the same height as well as the same energy and so they have the same speed.

Note that balls will take about 2 seconds to be able to hit the ground.

The horizontal projection velocity of the second ball can be changed so that the balls arrive at the ground at the same time and so the balls will be closest to one another if the second ball is thrown.

Learn more about projection velocity  from

brainly.com/question/4582453

#SPJ1

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Art [367]

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4 0
2 years ago
why does diving 30m below sea level affect our bodies more than being in a building 30m above sea level
Genrish500 [490]
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5 0
3 years ago
Alex is asked to move two boxes of books in contact with each other and resting on a frictionless floor. He decides to move them
Anit [1.1K]

Answer:

2.8 N

Explanation:

Fp = 7.7 N

mA = 12.1 kg

mB = 7 kg

Let a be the acceleration and Fc be the contact force between A and B.

By the free body diagram, use Newton's second law

Fp - Fc = mA x a ..... (1)

Fc = mB x a ..... (2)

Adding both the equations

Fp = (mA + mB) x a

7.7 = (12.1 + 7) x a

a = 0.4 m/s^2

Substitute this value in equation (2), we get

Fc = 7 x 0.4 = 2.8 N

Thus, the contact force between the two blocks is 2.8 N.

Explanation:

3 0
3 years ago
In the parts that follow select whether the number presented in statement A is greater than, less than, or equal to the number p
OleMash [197]

Answer:

1)   A> B, 2)  A = B,  3)    A> B

Explanation:

When a figure is given the number of significant figures to determine the precision or uncertainty the number

1) the uncertainty in the number with three significant figures is less than the number with two significant figures

statement A 2.6

statement B 2.57

        A> B

2) decalration A

         2,567 + 3,146 = 5,713

with two figures it remains

             5.7

statement B

         2.6 + 3.1 = 5.7

 A = B

3) for the product the result is with the number that has the least significant figures

statement A

rectangles area

   2.536 * 1.4 = 3.6

  statement B

    2.536 * 1.41 = 3.58

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7 0
3 years ago
A photon detector captures a photon with an energy of 4.29 ✕ 10−19 J. What is the wavelength, in nanometers, of the photon?
serious [3.7K]

Answer :  The wavelength of photon is, 4.63\times 10^{2}nm

Explanation : Given,

Energy of photon = 4.29\times 10^{-19}J

Formula used :

E=h\times \nu

As, \nu=\frac{c}{\lambda}

So, E=h\times \frac{c}{\lambda}

where,

\nu = frequency of photon

h = Planck's constant = 6.626\times 10^{-34}Js

\lambda = wavelength of photon  = ?

c = speed of light = 3\times 10^8m/s

Now put all the given values in the above formula, we get:

4.29\times 10^{-19}J=(6.626\times 10^{-34}Js)\times \frac{(3\times 10^{8}m/s)}{\lambda}

\lambda=4.63\times 10^{-7}m=4.63\times 10^{-7}\times 10^9nm=4.63\times 10^{2}nm

Conversion used : 1nm=10^{-9}m

Therefore, the wavelength of photon is, 4.63\times 10^{2}nm

6 0
3 years ago
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