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son4ous [18]
1 year ago
10

a ball is projected horizontally from the top the building.One second later another ball is projected horizontally from the same

point with the same velocity.At what point In the motion will the balls be closest to each other?Will the first ball always be travelling faster than the second ball?What will be the time interval between them when the ball hits the ground?Can the horizontal projection velocity of the second ball be changed so that the balls arrive at the ground at the same time?
Physics
1 answer:
stellarik [79]1 year ago
8 0

The point In the motion that the balls will be closest to each other is as at the time as the second ball is thrown or lunched.

<h3>Will the first ball always be travelling faster than the second ball?</h3>

No, The two motions are said to be parallel to one another, so they that they both the same timing. Hence, the time it takes for both balls to be able to fall to the ground is said to be the same.

Yes, the both balls have the same speed because of  two balls are said to hit the ground, they are said to be done at the same height as well as the same energy and so they have the same speed.

Note that balls will take about 2 seconds to be able to hit the ground.

The horizontal projection velocity of the second ball can be changed so that the balls arrive at the ground at the same time and so the balls will be closest to one another if the second ball is thrown.

Learn more about projection velocity  from

brainly.com/question/4582453

#SPJ1

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3 0
3 years ago
Two circles are drawn in a 12-inch by 14-inch rectangle. Each circle has a diameter of 6 inches. If the circles do not extend be
Dennis_Churaev [7]

Answer:

d = 10 inch

Explanation:

The farthest distance between the centers, is along the diagonal of the rectangle. Therefore, we need to calculate the diagonal of the rectangle, but counting the fact that we have both circles.

So if, one side is 12 inch, and the other is 14 inch, we can use the Pitagoras theorem which is:

d = √(a²) + (b)²

Where a and b, are the lenght of the rectangle, but without the lenght  of the diameter of both circles.

With this, the expression is this:

d = √(14 - 6)² + (12 - 6)²

d = √64+36

d = √100

d = 10 inches

6 0
3 years ago
Wave-particle duality tells us that wave and particle models apply to all objects whatever the size, so why don't we observe wav
Genrish500 [490]

Answer:

Because the wavelengths of macroscopic objects are too short for them to be detectable.

Explanation:

Wavelength of an object is given by de Broglie wavelength as:

\lambda=\frac{h}{mv}

Where, 'h' is Planck's constant, 'm' is mass of object and 'v' is its velocity.

So, for macroscopic objects, the mass is very large compared to microscopic objects. As we can observe from the above formula, there is an inverse relationship between the mass and wavelength of the object.

So, for vary larger masses, the wavelength would be too short and one will find it undetectable. Therefore, we don't observe wave properties in macroscopic objects.

4 0
3 years ago
What is the kinetic energy of a 1.00g hailstone falling at 8.50m/s
bearhunter [10]

Answer:

36.125 J

Explanation:

The formula for kinetic energy is KE = .5(m)(v²).

Using the given information, mass = 1 g and v = 8.50.  Plug that information into the equation.  KE = .5(1)(8.50²) = 36.125 J.

4 0
3 years ago
An undiscovered planet, many lightyears from Earth, has one moon in a periodic orbit. This moon takes 17601760 × 103 seconds (ab
Yuliya22 [10]

Answer:

The value is a_r  = 3.81 *10^{-3} m/s^2

Explanation:

Generally the moon's radial acceleration is mathematically represented as

a_r  =  r *  w^2

Here w is the angular velocity which is mathematically represented as

w =\frac{2 \pi }{ T}

substituting 1760 * 10^3 \ seconds for T(i.e the period of the moon ) we have

w =\frac{2  * 3.142 }{  1760 * 10^3}

=> w = 3.57 *10^{-6} \  rad/s

From the question r(which is the radius of the orbit ) is evaluated as

r =  R + H

substitute 3.60 * 10^6 m for R and 295.0 * 10^6  \  m H

       r =  295.0 * 10^6   +3.60 * 10^6

=>   r =  2.986 *10^{8} \  m

So

    a_r  =   2.986 *10^{8} *  ( 3.57 *10^{-6} )^2

      a_r  = 3.81 *10^{-3} m/s^2

4 0
3 years ago
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