The range of a projectile is the maximum horizontal distance between the point of origin to the end point. It can be calculated through the equation,
range = v²sin2θ/g
where v is the initial velocity, θ is the angle, and g is the gravitational constant.
Substituting the known values,
range = (36 m/s)² x (sin2(28°)) / 9.8 m/s²
range = 109.64 m
Thus, the range of the golf ball is approximately 109.64 m.
Answer:
a)W= 1 J
b)W= 1 J
c)W= 0 J
Explanation:
Given that
m = 5 kg
Coefficient of kinetic friction,K=0.5
d= 10 cm
We know that if velocity is constant it means that the acceleration of the system is zero.Or we can say that all forces are balance in the system.
We know that work is the dot product of force and displacement
W= F.d
The friction force on the box
Fr= K m g
Fr= 0.5 x 5 x 10 = 25 N ( take g =10 m/s²)
Fr=25 N
a)
Acceleration a= 0
So horizontal force F = Fr
W = Fr.d
W=10 x 0.1 J
W= 1 J
b)
The work done by friction force
W= 1 J
c)
The net force on the system is zero because acceleration is zero.
F= 0
So
W= 0 J
Electricity passes through it
Answer is Option C
hope it helps you
