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tigry1 [53]
3 years ago
13

Basking in the sun, a 1.10 kg lizard lies on a flat rock tilted at an angle of 15.0° with respect to the horizontal. What is the

magnitude of the normal force exerted by the rock on the lizard? a. 10.5 N c. 10.4 N b. 2.8 N d. -10.5 N
Physics
1 answer:
Ray Of Light [21]3 years ago
3 0

10.4 N

Given

m = 1.10 kg

θ = 15.0°

g = 9.81 m/s2

Solution

Fnet, y = ΣF y = Fn − Fg, y = 0

Fn = Fg, y = Fg

cosθ = mgcosθ

Fn = (1.10 kg)(9.81 m/s2

)(cos15.0°) = 10.4 N

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The Earth's Radius is 6.3710x106 m and mass is 5.9742x1024 kg. What is the acceleration due to gravity at Mount Everest (elevati
Shalnov [3]

Answer is

9.773m/s^2

-----------------------------------------------------------------------------

Given,

h=8848m

The value of sea level is 9.08m/s^2. So, Let g′ be the acceleration due to the gravity on Mount Everest.

g′=g(1 − 2h/h)

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=9.8(1 − 0.00276)

9.8×0.99724

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Thus, the acceleration due to gravity on the top of Mount Everest is =9.773m/s^2

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3 0
2 years ago
Why do we feel the force of gravity from the Earth but we don’t feel the force of gravity from the moon?
Zigmanuir [339]

Answer:

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Explanation:

Hope this helped!!

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