What is 3/8 written as a percent?

2 answers:

8 0

3/8 written as a percent is 37.5%. All you have to do is divide the two numbers in the calculator to get the answer you need :) I hope this helps :D

trapecia [35]3 years ago

7 0

<span>37.5% because its really easy to do x</span>

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What are the values of the regrouped amounts in the multiplication 435 times 17

jok3333 [9.3K]

Https://www.google.com/url?sa=t&rct=j&q=&esrc=s&source=web&cd=3&cad=rja&uact=8&ved=0ahUKEwi338DN1erP...

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5 0

3 years ago

Write the recursive rule and the iterative rule for the following sequence: 10, 6, 2, -2, -6

barxatty [35]

The recursive rule is
$a_n=a_{n-1}+(-4)$ .
The iterative rule is
$a_n=14-4n$

The recursive rule is given by the formula
$a_n=a_{n-1}+d$ , where d is the common difference. Our common difference is -4, which gives us the recursive rule above.

The iterative rule begins with the formula
$a_n=a_1+d(n-1)$ , where a₁ is the first term and d is the common difference. Our first term is 10 and our common difference is -4:
$a_n=10+(-4)(n-1)
\\\text{Using the Distributive Property,}
\\
\\a_n=10+(-4*n)+(-4*-1)
\\
\\a_n=10-4n+4
\\
\\\text{Combining like terms,}
\\
\\a_n=14-4n$

7 0

3 years ago

Which of these can be written as an equation?

Katyanochek1 [597]

Your answer would be choice b

6 0

3 years ago

I need answer for this math problem

tekilochka [14]

Answer:

3h²

Step-by-step explanation:

factor or breakdown 3h² : 3 * h * h

factor or breakdown 3h³ : 3 * h * h * h

Now, we can see that 3 * h * h is common so 3h² is the gcf.

6 0

2 years ago

Read 2 more answers

Please help radical expression dividing

77julia77 [94]

$\bf \cfrac{\sqrt[4]{63}}{4\sqrt[4]{6}}\qquad 
\begin{cases}
63=3\cdot 3\cdot 7\\
6=2\cdot 3
\end{cases}\implies \cfrac{\sqrt[4]{3\cdot 3\cdot 7}}{4\sqrt[4]{2\cdot 3}}\implies \cfrac{\underline{\sqrt[4]{3}}\cdot \sqrt[4]{3}\cdot \sqrt[4]{7}}{4\sqrt[4]{2}\cdot \underline{\sqrt[4]{3}}}
\\\\\\
\cfrac{\sqrt[4]{3}\cdot \sqrt[4]{7}}{4\sqrt[4]{2}}\implies \cfrac{\sqrt[4]{3\cdot 7}}{4\sqrt[4]{2}}\implies \cfrac{\sqrt[4]{21}}{4\sqrt[4]{2}}$

$\bf \textit{now, rationalizing the denominator}\\\\
\cfrac{\sqrt[4]{21}}{4\sqrt[4]{2}}\cdot \cfrac{\sqrt[4]{2^3}}{\sqrt[4]{2^3}}\implies \cfrac{\sqrt[4]{21}\cdot \sqrt[4]{8}}{4\sqrt[4]{2}\cdot \sqrt[4]{2^3}}\implies \cfrac{\sqrt[4]{21\cdot 8}}{4\sqrt[4]{2\cdot 2^3}}\implies \cfrac{\sqrt[4]{168}}{4\sqrt[4]{2^4}}
\\\\\\
\cfrac{\sqrt[4]{168}}{4\cdot 2}\implies \cfrac{\sqrt[4]{168}}{8}$

and is all you can simplify from it.

so... all we did, was rationaliize it, namely, "getting rid of the pesky radical at the bottom", we do so by simply multiplying it by something that will raise the radicand, to the same degree as the root, thus the radicand comes out.

6 0

3 years ago