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astra-53 [7]
4 years ago
15

A water balloon dropped from a window high above the ground falls y = 4.9t2 m in t sec. find the balloon’s (a) average speed dur

ing the first 3 sec of fall. (b) speed at the instant t = 3.
Physics
1 answer:
satela [25.4K]4 years ago
4 0
For the average speed, I multiplied 4.9 by 3 squared to receive 44.1, then divided that by 3 to receive 14.7 m/s. 4.9 X 4.9 X 4.9 = 44.1(Distance traveled / fall time)44.1 ÷ 3 = 14.7 m/s

For the speed at t = 3, I took the derivative of 4.9t2 to make it 2(4.9)t and then plugged in 3 to receive an answer of 29.4 m/s. derivative   =2(4.9)t                    =2(4.9)3                    =29.4 m/s
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Analyze why we say an object is accelerating when we usually mean that it is speeding up and an object slowing down also is acce
dem82 [27]

(And don't forget that an object going around a curve at a constant speed is also accelerating.)

I believe there are two reasons:

1). The term is inadequately taught in the American public school system ... along with much of the rest of Science and Math in general.

2). The word became permanently and indelibly corrupted when the automotive industry decided to name the gas pedal the "accelerator".

3 0
4 years ago
a bat experts a 120 N force on a 0.134 kg baseball for 0.04 seconds. what impolse is excerted on the bat
musickatia [10]
The impulse exerted by a force F on an object in a time \Delta t is given by
I = F \Delta t
In our problem, we have a force of 120 N: F=120 N, applied to the baseball for a time of \Delta t=0.04 s. Therefore the impulse is
I=F \Delta t = (120 N)(0.04 s)=4.8 Ns
3 0
4 years ago
Calculate the power of the eye in D when viewing an object 5.70 m away. (Assume the lens-to-retina distance is 2.00 cm. Enter yo
Tems11 [23]

Answer:

Power=50.17dioptre

Power=50.17D

Explanation:

P=1/f = 1/d₀ + 1/d₁

Where d₀ = the eye's lens and the object distance= 5.70m=

d₁= the eye's lens and the image distance= 0.02m

f= focal length of the lense of the eye

We know that the object can be viewed clearly by the person ,then image and lens of the eye's distance needs to be equal with the retinal and the eye lens distance and this distance is given as 0.02m

Therefore, we can calculate the power using above formula

P= 1/5.70 + 1/0.02

Power=50.17dioptre

Therefore, the power the eye's is using to see the object from distance is 5.70D

3 0
4 years ago
Can you answer this math homework? Please!
kap26 [50]

\large \mathfrak{Solution : }

9. An object which is in circular motion (moving along a circle) is said to be accelerating because it changes it's direction constantly even if it is moving with a constant speed. cuz acceleration is change in either magnitude or direction of an object with respect to time.

therefore, it's still acceleration as change in direction with time.

10. Average speed of an object can be calculated by dividing the total distance covered by an object by time taken to cover that distance.

i.e

  • \boxed{speed =  \dfrac{distance}{time} }

it can be re- arranged to find the distance as :

  • \boxed{distance = speed \times time}

  • time =  \dfrac{distance}{speed}

11. speed = 20 m/s : conversion into km/h

distance covered : 4 km = 4000 m

  • time =  \dfrac{distance}{speed}

  • t =  \dfrac{4000}{20}

  • t =  200 \:  \: sec

time taken = 200 seconds

12. let's use the first equation of motion to find the acceleration :

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  • 50 = 80 + 120a

  • 50 - 80 = 120a

  • a =  \dfrac{ - 30}{120}

  • a = -   \dfrac{1}{4} m/s {}^{2}

  • - 0.25 \:  \: m/s {}^{2}
3 0
3 years ago
State the pressure law?
yarga [219]
The pressure law states: "For a fixed mass of gas, at a constant volume, thepressure<span> (p) is directly proportional to the absolute temperature (T)."</span>
4 0
3 years ago
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