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4 years ago

Is diverse families positive or negative

Physics

1 answer:

nataly862011 [7]4 years ago

6 0

Think its Positive
hope this helpes

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In a science fiction novel two enemies, Bonzo and Ender, are fighting in outer spce. From stationary positions, they push agains

Bingel [31]

Answer:

2.461

Explanation:

Let mass of Bonzo = m1

Mass of Ender =m2

When they push eachother from stationary position

Initial velocity of Bonzo = Vib=0 m/s

Final velocity of Bonzo = Vfb= 1.3 m/s

Initial velocity of Ender = Vie= 0 m/s

Final velocity of Ender = Vfe= -3.1 m/s

We know initial momentum = final momentum

==> m1Vib+m2Vie = m1Vfb+m2Vfe

==> 0+0= m1×1.3 +m2×(-3.1)

==> 1.3m1-3.1m2=0

==> 1.3 m1 = 3.2 m2

==> m1/m2 = 3.2/1.3

==> m1/m2 = 2.461

6 0

4 years ago

In our new car, we were able to drive 30 miles in a half an hour. From this information, we can determine the car's

Ronch [10]

Average speed.
(Not velocity.)

5 0

3 years ago

If you are running at the speed of sound, would you still be able to hear the music in your headphones?

Alex Ar [27]

Ask Barry Allen he’s the faster man alive

4 0

3 years ago

shows a conical pendulum, in which the bob (the small object at the lower end of the cord) moves in a horizontal circle at const

Contact [7]

Answer:

a) $T=0.40 N$

b) $T=1.9 s$

Explanation:

Let's find the radius of the circumference first. We know that bob follows a circular path of circumference 0.94 m, it means that the perimeter is 0.94 m.

The perimeter of a circunference is:

$P=2\pi r=0.94$

$r=\frac{0.94}{2\pi}=0.15 m$

Now, we need to find the angle of the pendulum from vertical.

$tan(\alpha)=\frac{r}{L}=\frac{0.15}{0.90}=0.17$

$\alpha=9.44 ^{\circ}$

Let's apply Newton's second law to find the tension.

$\sum F=ma_{c}=m\omega^{2}r$

We use centripetal acceleration here, because we have a circular motion.

The vertical equation of motion will be:

$Tcos(\alpha)=mg$ (1)

The horizontal equation of motion will be:

$Tsin(\alpha)=m\omega^{2}r$ (2)

a) We can find T usinf the equation (1):

$T=\frac {mg}{cos(\alpha)}=\frac{0.04*9.81}{cos(9.44)}=0.40 N$

We can find the angular velocity (ω) from the equation (2):

$\omega=\sqrt{\frac{Tsin(\alpha)}{mr}}=3.31 rad/s$

b) We know that the period is T=2π/ω, therefore:

$T=\frac{2\pi}{\omega}=\frac{2\pi}{3.31}=1.9 s$

I hope it helps you!

8 0

3 years ago

Present day Earth is in the _______.

Allushta [10]

Answer:

Cenozoic era

Explanation:

8 0

3 years ago