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3 years ago

10

Find the magnitude of the impulse delivered to a soccer ball when a player kicks it with a force of 1450 N . Assume that the pla

yer's foot is in contact with the ball for 5.50×10−3 s .

1 answer:

defon3 years ago

5 0

Answer:

7.98 Newton Seconds

Explanation:

J = F * (Δt)

J = 1450 (5.5 * 10^-3)

J = 7.975

We only use three significant digits, so our answer becomes 9.98

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How does the mass of the melted sundae compare to when it was first made? this for science

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<h3><u>Answer:</u></h3>

When it was first made, it was heavier

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2 years ago

The intensity level of a "Super-Silent" power lawn mower at a distance of 1.0 m is 100 dB. You wake up one morning to find that

Gala2k [10]

Answer:

The intensity level in the room is 63 dB

Explanation:

To calculate the intensity of sound in the room, we use the equation of definition of decibels

β = 10 log (I / Io) (1)

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To calculate the intensity we will use the initial data and remember the power of the emitted sound is constant, in addition that the sound propagates in three-dimensional form or on a spherical surface

I = P/A ⇒ P = I A

The area of a sphere is 4 π r², where I can calculate of 1

β/10 = log (I/Io)

I / Io = ${10}^{\beta /10}$

I = Io ${10}^{\beta /10}$

I = 1 10⁻¹² 10⁽¹⁰⁰/¹⁰⁾ = 1 10⁻¹² 10¹⁰

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With this we can calculate the intensity for a distance of 20 m

I = 1.0 10⁻² / ( 4π 20²)

I = 2.0 10⁻⁶ W/m²

We have already found the intensity at the point of interest, so we can calculate the intensity in decibels at this point with equation 1

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3 years ago

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3 years ago

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3 years ago

Two electrons with a charge of magnitude 1.6×10-19 C in an atom are separated by 1.5×10-10 m, the typical size of an atom. What

vesna_86 [32]

Answer:

$1.02\cdot 10^{-8} N$ , repulsive

Explanation:

The magnitude of the electric force between two charged particles is given by Coulomb's law:

$F=k\frac{q_1 q_2}{r^2}$

where:

$k=8.99\cdot 10^9 Nm^{-2}C^{-2}$ is the Coulomb's constant

$q_1, q_2$ are the two charges of the two particles

r is the separation between the two charges

The force is:

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- Attractive if the two charges have opposite signs

In this problem, we have two electrons, so:

$q_1=q_2=1.6\cdot 10^{-19}C$ is the magnitude of the two electrons

$r=1.5\cdot 10^{-10} m$ is their separation

Substituting into the formula, we find the electric force between them:

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And the force is repulsive, since the two electrons have same sign charge.

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3 years ago