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Maksim231197 [3]
3 years ago
5

When was the first ozone hole discovered ​

Physics
1 answer:
Sveta_85 [38]3 years ago
5 0

Answer:  July 1st 1910

Explanation:

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A potter's wheel is rotating around a vertical axis through its center at a frequency of 2.0 rev/srev/s . The wheel can be consi
vagabundo [1.1K]

Answer:1.7 rev/s

Explanation:

Given

Frequency of wheel N_1=2\ rev/s

angular speed \omega_1=2\pi N_1=4\pi\  rad/s

mass of wheel m_1=4.5\ kg

diameter of wheel d_1=0.30\ m=30\ cm

radius of wheel r_1=\frac{d_1}{2}=\frac{30}{2}=15\ cm

mass of clay m_2=2.8\ kg

the radius of the chunk of clay r_2=8\ cm

Moment of inertia of Wheel

I_1=\dfrac{m_1r_1^2}{2}=\dfrac{4.5\times 15^2}{2}\ kg-cm^2

Combined moment of inertia of wheel and clay chunk

I_2=\dfrac{m_1r_1^2}{2}+\dfrac{m_2r_2^2}{2}=\dfrac{4.5\times 15^2}{2}+\dfrac{2.8\times 8^2}{2}\ kg-cm^2

Conserving angular momentum

\Rightarrow I_1\omega_1=I_2\omega_2\\\Rightarrow \dfrac{4.5\times 15^2}{2}\cdot 4\pi=(\dfrac{4.5\times 15^2}{2}+\dfrac{2.8\times 8^2}{2})\omega_2\\\\\Rightarrow \omega _2=\dfrac{4\pi }{1+\dfrac{2.8}{4.5}\times (\dfrac{8}{15})^2}=\dfrac{4\pi}{1+0.1769}=0.849\times 4\pi

Common frequency of wheel and chunk of clay is

\Rightarrow N_2=\dfrac{4\pi \times 0.849}{2\pi}=1.698\approx 1.7\ rev/s

5 0
3 years ago
What is homeostasis?
SashulF [63]
<span>Homeostasis maintains internal balance of the cell.-- Things like shiver if cold sweating if hot to maintain internally </span>
3 0
3 years ago
Read 2 more answers
Only the bottom the photo is here
Burka [1]
If we're talking about part c then

igneous rock + weathering and erosion = sedimentary rock

sedimentary rock + heat and pressure = metamorphic rock

magma + cooling = igneous rock
7 0
3 years ago
Read 2 more answers
Which is not an example of how an object gains elastic potential energy by stretching?
lora16 [44]
C because you don’t put a force of which you choose and the force wouldn’t be strong enough
4 0
4 years ago
A diver running 1.8 m/s dives out horizontally from the edge of a vertical cliff and reaches the water below 3s later. How high
Marysya12 [62]

We use kinematic equation,

h=ut+\frac{1}{2} gt^2

Here, h is vertical height, u is initial vertical velocity, t is time taken and g is acceleration due to gravity.

As diver dives out horizontally, his velocity is directed horizontally; that is, the initial vertical velocity is 0. So above equation becomes

h=\frac{1}{2} gt^2

Given, t =3 s.

Therefore,

h=\frac{1}{2}\times 9.8m/s^2(3\ s)^2 =0.5\times 9.8 m/s^2\times 9 s^2\\\\h=44.1\ m.

Now the horizontal distance of the diver to hit the water from base,  

=1.8\ m/s \times 3\ s=5.4\ m

6 0
4 years ago
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