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nexus9112 [7]
3 years ago
13

What percent of 80 is 28

Mathematics
2 answers:
Svet_ta [14]3 years ago
8 0

Answer:

35%

Step-by-step explanation:

Of means multiply,  is means equals

P * 80 = 28

Divide by 80

P * 80/80 = 28/80

P = .35

Multiply by 100 to get percent

p = 35 %

serious [3.7K]3 years ago
5 0

Answer:

35%

Step-by-step explanation:

easy way to remember: \frac{28}{80} *1 00

= 0.35 *100

= 35%

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<em>_______________</em>

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Question 2
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A survey of 865 voters in one state reveals that 408 favor approval of an issue before the legislature. Construct the 95% confid
katrin [286]

Answer:

The 95% confidence interval for the true proportion of all voters in the state who favor approval is (0.4384, 0.5050).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 865, \pi = \frac{408}{865} = 0.4717

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4717 - 1.96\sqrt{\frac{0.4717*0.5283}{865}} = 0.4384

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4717 + 1.96\sqrt{\frac{0.4717*0.5283}{865}} = 0.5050

The 95% confidence interval for the true proportion of all voters in the state who favor approval is (0.4384, 0.5050).

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3 years ago
An apartment has
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When you divide 972 by 10.8 you get the answer of 90. Hope this helps :)


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3 years ago
Solve for w<br> -2w=-30<br> Simplify your answer as much as possible.<br><br> 20 POINTS
RUDIKE [14]

Answer:

C

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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