Answer:
P4 + 5O2 → P4O10
Explanation:
White Phosphorus - P4
Dioxygen - O2
Tetraphosphorus Decaoxide - P4O10
Food web shows the cycle of energy that is transferred from one organism to another in that web.
<u>Explanation:</u>
A food web (or nourishment cycle) is the natural interconnection of natural pecking orders and a graphical portrayal (generally a picture) of what-eats-what in an environmental network. Another name for nourishment web is customer asset framework.
Arrows on a food web, or food web, speak to the progression of vitality. The situation of the bolts in an evolved way of life or nourishment web is significant. The bolts consistently show the heading of the vitality as it is moved starting with one life form then onto the next. The progression of vitality can likewise be spoken to inside a vitality pyramid.
I can't answer this question without knowing what the specific heat capacity of the calorimeter is. Luckily, I found a similar problem from another website which is shown in the attached picture.
Q = nCpΔT
Q = (1.14 g)(1 mol/114 g)(6.97 kJ/kmol·°C)(10°C)(1000 mol/1 kmol)
<em>Q = +6970 kJ</em>
Answer:
To calculate the pressure when temperature and volume has changed, we use the equation given by combined gas law. The equation follows:
\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}
T
1
P
1
V
1
=
T
2
P
2
V
2
where,
P_1,V_1\text{ and }T_1P
1
,V
1
and T
1
are the initial pressure, volume and temperature of the gas
P_2,V_2\text{ and }T_2P
2
,V
2
and T
2
are the final pressure, volume and temperature of the gas
We are given:
\begin{gathered}P_1=760mmHg\\V_1=175L\\T_1=15^oC=[15+273]K=288K\\P_2=640mmHg\\V_2=198L\\T_2=?K\end{gathered}
P
1
=760mmHg
V
1
=175L
T
1
=15
o
C=[15+273]K=288K
P
2
=640mmHg
V
2
=198L
T
2
=?K
Putting values in above equation, we get:
\begin{gathered}\frac{760mmHg\times 175L}{288K}=\frac{640mmHg\times 198L}{T_2}\\\\T_2=274K\end{gathered}
288K
760mmHg×175L
=
T
2
640mmHg×198L
T
2
=274K
Hence, the temperature when the volume and pressure has changed is 274 K
Complete combustion of acetylene generated carbon dioxide and water. This can be represent by following reaction
2C2H2 + 5O2 → 4CO2 + 2H2O
(2 mole) (4 mole)
From the above balanced reaction, it can be seen that 2 mole of acetylene on complete combustion generates 4 moles of carbon dioxide
i.e. 2 mole of C2H2 ≡ 4 mole of CO2
∴ 1.3 mole of C2H2 ≡ (4 X 1.3)/2 = 2.6 mole of CO2
Now, 1 mole of CO2 = 44 g
∴ 2.6 mole of CO2 = (44 X 2.6) = 114.4 g
Thus, <span>114.4 grams of carbon dioxide are produced from the combustion of 1.3 moles of acetylene</span>
