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Oksana_A [137]
3 years ago
6

Write a word equation for this reaction S + 02 → SO2Whoever Answer right will get brainliest ​

Chemistry
1 answer:
storchak [24]3 years ago
6 0

\huge \mathcal{Answer࿐ }

The word equation for above chemical equation is :

Sulphur + Oxygen \rightarrow Sulphur dioxide

_____________________________

\mathrm{ \#TeeNForeveR}

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Simplify - Factor a
Dmitriy789 [7]

Answer:

Option 1

Explanation:

Option number 1 is the most compact one which indicates it is a solid

7 0
3 years ago
Heavy water contains
Fed [463]

Explanation:

The difference, though, lies in the hydrogen atoms. In ordinary water, each hydrogen atom has just a single proton in its nucleus. In heavy water, each hydrogen atom is indeed heavier, with a neutron as well as a proton in its nucleus.

8 0
3 years ago
A chemical reaction is synonymous to a ________. A chemical reaction is synonymous to a ________. chemical change rise in temper
Pie

Answer:

CHEMICAL CHANGE

Explanation:

Chemical reaction is synonymous to a chemical change. A chemical change is one which is not easily reversed and in which a new substance is formed.

The reactants are converted to products by the rearrangement of the constituent atoms to form a different compound.

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3 0
4 years ago
Consider the data presented below. time (s) 0 40 80 120 160 moles of a 0.100 0.067 0.045 0.030 0.020 part a part complete determ
Whitepunk [10]
To determine which order of the reaction it is, first we need to calculate the rate of change of moles.
the data is as follows 
time         0         40        80       120       160
moles    0.100   0.067  0.045    0.030    0.020


Q1)
for the first 40 s change of moles ;
      = -d[A] / t
      = - (0.067-0.100)/40s
      = 8.25 x 10⁻⁴ mol/s
for the next 40 s
      = -(0.045-0.067)/40
      = 5.5 x 10⁻⁴ mol/s
the 40 s after that
      = -(0.030-0.045)/40 s 
     = 3.75 x 10⁻⁴ mol/s
k - rate constant
and A is the only reactant that affects the rate of the reaction

rate = k [A]ᵇ
8.25 × 10⁻⁴ mol/s = k [0.100 mol]ᵇ ----1
5.5 x 10⁻⁴ mol/s = k [0.067 mol]ᵇ   -----2
divide the 2nd equation by the 1st equation
1.5 = [1.49]ᵇ
b is almost equal to 1
Therefore this is a first order reaction

Q2)
to find out the rate constant(k), we have to first state the equation for a first order reaction.
rate = k[A]ᵇ
As A is the only reactant thats considered for the rate equation. 
Since this is a first order reaction,
b = 1
therefore the reaction is 
rate = k[A]
substituting the values,
8.25 x 10⁻⁴ mol/s = k [0.100 mol]
k = 8.25 x 10⁻⁴ mol/s /0.100mol
   = 8.25 x 10⁻³ s⁻¹

7 0
4 years ago
PLEASE HELP ME TAKE SOO LONG! (ima fail this test!) its a study guide!
kakasveta [241]

I think it might be C or D

6 0
3 years ago
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