Answer:
The answer is in the picture, good luck :)
Step-by-step explanation:
This is kind of off topic for math but I still need to know the answer, so I’ve finished all my math work and I know my work is
1 answer:
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Answer:
<u>Q/ Draw a line ; Ans; </u>
*explain ; We put the 5 in the denominator and 5 multiply 1 + 4 so equal 9 so the choice 9/5 .
Ans; 7/3—> 2 1/3
*explain ; We put the 3 in the denominator and 3 multiply 2 + 1 so equal 7 so the choice 7/3 .
Ans; 12/10 —> 1 1/5
*explain; simple (12 and 10) ÷ 2 so equal 6/5
We put the 5 in the denominator and 5 multiply 1 + 1 so equal 6 so the choice 6/5 =12/10 .
<u>Q/ Compare the fractions;Ans;</u>
* explain; 2/3 = 0.66 and 14/6=2.33 so 2.33 greater from 0.66 so 14/6 greater from 2/3 .
* explain; 3/8 = 0.375 and 8/3=2.666 so 2.666 greater from 0.375 so 8/3 greater from 3/8 .
* explain; 2 1/6 —> We put the 6 in the denominator and 6 multiply 2 + 1 so equal 13 so equal 13/6
13/6 = 2.16 and 5/9=0.55 so 2.16 greater from 0.55 so 13/6 = 2 1/6 greater from 5/9 .
<u>Q/Add; Ans;</u>
<u>Q/Subtract; Ans;</u>
<u>Q/ Multiply;Ans;</u>
<u>Q/Divide;Ans;</u>
I hope I helped you^_^
Sum/difference:
Let
This means that
Now, assume that is rational. The sum/difference of two rational numbers is still rational (so 5-x is rational), and the division by 3 doesn't change this. So, you have that the square root of 8 equals a rational number, which is false. The mistake must have been supposing that
was rational, which proves that the sum/difference of the two given terms was irrational
Multiplication/division:
The logic is actually the same: if we multiply the two terms we get
if again we assume x to be rational, we have
But if x is rational, so is -x/15, and again we come to a contradiction: we have the square root of 8 on one side, which is irrational, and -x/15 on the other, which is rational. So, again, x must have been irrational. You can prove the same claim for the division in a totally similar fashion.