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3 years ago

Simplify 6m plus 2m minus 5

Mathematics

2 answers:

mr Goodwill [35]3 years ago

6 0

Answer:

8m-5

Step-by-step explanation:

Lets write this out in an equation.The plus means addition and the minus means subtraction.

6m+2m-5

Since there is two things with the same variable we can combine them.

8m-5

That is as simple as it gets.

Furkat [3]3 years ago

3 0

6m plus 2m minus 5

If you turn that into an algebraic expression, it would look something like this:

6m + 2m - 5

Now, you combine like terms.

6m + 2m - 5 = 8m + 5.

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WILL MARK BRAINLIST

Deffense [45]

Answer:

slope= 0

y intercept= -27

Step-by-step explanation:

4y= -108

y= -27

slope= 0

y intercept= -27

since this line will always have -27 as its y value.

5 0

2 years ago

Ship collisions in the Houston Ship Channel are rare. Suppose the number of collisions are Poisson distributed, with a mean of 1

alexandr1967 [171]

Answer:

$a) \simeq 0.3012$ $b) \simeq 0.0494$ c) $\simeq 0.2438$

Step-by-step explanation:

Rate of collision,

1.2 collisions every 4 months

or, $\frac{1.2}{4}$

= 0.3 collisions per month

So, the Poisson distribution for the random variable no. of collisions per month (X) is given by,

P(X =x) = $\frac{e^{-\lambda}\times {\lambda}^{x}}}{x!}
$

for x ∈ N ∪ {0}

= 0 otherwise --------------------------------------(1)

here, $\lambda = 0.3$ collision / month

No collision over a 4 month period means no collision per month or X =0

Putting X = 0 in (1) we get,

P(X = 0) = $\frac{e^{-0.3}\times {\0.3}^{0}}{0!}
$

$\simeq 0.7408182207$ ------------------------------------(2)

Now, since we are calculating this for 4 months,

so, P(No collision in 4 month period)

= $0.7408182207^{4}$

$\simeq 0.3012$ -----------------------------------------------------------(3)

2 collision in 2 month period means 1 collision per month or X =1

Putting X =1 in (1) we get,

P(X =1) = $\frac{e^{-0.3}\times {\0.3}^{1}}{1!}
$

$\simeq 0.2222454662$ ------------------------------------(4)

Now, since we are calculating this for 2 months, so ,

P(2 collisions in 2 month period)

= $0.2222454662^{2}$

$\simeq 0.0494$ -----------------------------------------(5)

1 collision in 6 months period means

$\frac{1}{6}$ collision per month

Now, P(1 collision in 6 months period)

= P( X = 1/6] (which is to be estimated)

= $\frac {P(X=0)\times 5 + P(X =1)\times 1}{6}$

= \frac {0.7408182207 \times 5 + 0.2222454662 \times 1}{6}[/tex]

$\simeq 0.6543894283$ -------------------------------------------(6)

So,

P(1 collision in 6 month period)

= $0.6543894283^{6}$

$\simeq 0.0785267444$ ------------------------------------------------(7)

So,

P(No collision in 6 months period)

= $(P(X =0)^{6}$

$\simeq 0.1652988882$ ---------------------------------(8)

so,

P(1 or fewer collision in 6 months period)

= (8) + (7 ) = 0.0785267444 +0.1652988882

$\simeq 0.2438$ ---------------------------------------------(9)

7 0

2 years ago

Plz help me with this!!!!!!!!

LenaWriter [7]

Answer: √y

<u>Step-by-step explanation:</u>

$\sqrt[6]{y^3}=y^{\frac{3}{6}}=y^{\frac{1}{2}}=\boxed{\sqrt y}$

4 0

3 years ago

The sum of 2 numbers is 38. one number is 10 more than the other.

son4ous [18]

Answer:

24, 14

Step-by-step explanation:

x + y = 38

x = 10 + y

You can substitute (10+y) into the top equation where the x is.

10 + y + y = 38

10 + 2y = 38

2y = 28

y = 14

Now plug 14 in for y in either equation to get x

x = 10 + 14

x = 24

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3 years ago

This equation shows how the total number of necklaces Denise owns is related to the amount of money she spends on additional nec

PtichkaEL [24]

Answer: n=90

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6 0

2 years ago