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Pepsi [2]
3 years ago
12

The crest of one wave with an amplitude of 4 m meets up with the crest of a second

Physics
1 answer:
trapecia [35]3 years ago
3 0

Answer:

Constructive

Explanation:

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The connections of many simple pieces in the brain is evidence of the:
olga55 [171]

Brian’s Complexity Brian’s Complexity Brian’s Complexity Brian’s Complexity

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3 years ago
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Why caring a body and moving with it is not a work done<br><br> Why :​
Alecsey [184]

Answer:

Work done on an object is equal to

FDcos(angle).

So, naturally, if you lift a book from the floor on top of the table you do work on it since you are applying a force through a distance.

However, I often see the example of carrying a book through a horizontal distance is not work. The reasoning given is this: The force you apply is in the vertical distance, countering gravity and thus not in the direction of motion.

But surely you must be applying a force (and thus work) in the horizontal direction as the book would stop due to air friction if not for your fingers?

Is applying a force through a distance only work if causes an acceleration? That wouldn't make sense in my mind. If you are dragging a sled through snow, you are still doing work on it, since the force is in the direction of motion. This goes even if velocity is constant due to friction.

Explanation:

8 0
2 years ago
What is the frequency of an x- ray if the wavelength is 4.5 E - 10m?
AnnZ [28]
V (speed) = F (frequency) x Wavelength
If we rearrange the formula, making frequency the subject;
F (frequency) = Speed ÷ Wavelength
F = 300,000 m\s x 4.5 e -10m
F = 0.08810409956 Hz
4 0
3 years ago
While on a playground, you and your niece take turns sliding down a frictionless slide. Your mass is 75 kg while your little nie
Olenka [21]

Answer:

c.

Explanation:

  • In absence of friction, total mechanical energy must be conserved.
  • This means that the change in gravitational potential energy (in magnitude) must be equal to the change in kinetic energy:

       \Delta K = \Delta U \\ \\  \frac{1}{2} * m* v^{2}  = m*g*h

  • As it can be seen, the mass m is on the both sides of the equation, which means that it can be simplified.
  • We can solve this equation for v (speed at the bottom) as follows:

        v = \sqrt{2*g*h}

  • As it can be seen, the mass has no part in the equation, so, due both are starting from the same height, both people have the same speed at the bottom.
  • The option c is the right one.
6 0
3 years ago
A jet plane lands with a speed of 100 m/s and can
kiruha [24]

Answer:

a) t = 20 [s]

b) Can't land

Explanation:

To solve this problem we must use kinematics equations, it is of great importance to note that when the plane lands it slows down until it reaches rest, ie the final speed will be zero.

a)

v_{f}=v_{i}-(a*t)

where:

Vf = final velocity = 0

Vi = initial velocity = 100 [m/s]

a = desacceleration = 5 [m/s^2]

t = time [s]

Note: the negative sign of the equation means that the aircraft slows down as it stops.

0 = 100 - 5*t

5*t = 100

t = 20 [s]

b)

Now we can find the distance using the following kinematics equation.

x -x_{o}=(v_{o}*t)+\frac{1}{2}*a*t^{2}

x - xo = distance [m]

x -xo = (0*20) + (0.5*5*20^2)

x - xo =  1000 [m]

1000 [m] = 1 [km]

And the runaway is 0.8 [km], therefore the jetplane needs 1 [km] to land. So the jetpalne can't land

4 0
3 years ago
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