For Newton's second law, the force is equal to the product between the mass and the acceleration of the rocket:

From which we can rewrite the acceleration as

where m=7.0 kg.
The velocity of the rocket is the derivative of the acceleration:

and if we substitute x=9.0 m, we find the rocket velocity after 9.0 m:
There doesn't seem to be any direct connection.
Answer:
1.7 m/s²
Explanation:
d = length of the ramp = 13.5 m
v₀ = initial speed of the skateboarder = 0 m/s
v = final speed of the skateboarder = 7.37 m/s
a = acceleration
Using the equation
v² = v₀² + 2 a d
7.37² = 0² + 2 a (13.5)
a = 2.01 m/s²
θ = angle of the incline relative to ground = 29.9
a' = Component of acceleration parallel to the ground
Component of acceleration parallel to the ground is given as
a' = a Cosθ
a' = 2.01 Cos29.9
a' = 1.7 m/s²