Ask question

Ask question

All categories

3 years ago

14

A long solenoid that has 1,140 turns uniformly distributed over a length of 0.350 m produces a magnetic field of magnitude 1.00

X 10^-4 T at its center. What current is required in the windings for that to occur? Apply the expression for the magnetic field along the axis of a solenoid to find the current.

1 answer:

Troyanec [42]3 years ago

3 0

Answer:

$I = 2.4 *10^{-2} A = 2.4 mA$

Explanation:

The magnetic field B inside long solenoid with current I is given as

$B = \frac{N \mu_o I}{L}$

where

N is number of turn of solenoids = 1140 turns

$\mu_0 = 4*\pi *10^{-7} T.m$

I is current that passes through solenoid

L is length along which current pass = 0.350 m

plugging value to get required value of current

$1.00*10^{-4} = \frac{1140*4*\pi *10^{-7} I}{0.350}$

$I = 2.4 *10^{-2} A = 2.4 mA$

You might be interested in

Which statement is true?

miv72 [106K]

B might be the correct answer

8 0

2 years ago

Explain whether a tennis ball dropped from a high distance experiences an elastic collision or inelastic collision

hodyreva [135]

I need help on that too poop head

4 0

2 years ago

When magma cools quickly, what kind of texture or

Ksivusya [100]

Answer:

a

Explanation:

when magma cools Crystal's form because the solution is super saturated with respect to some minerals if the magma cools quickly the crystals do not have much time to form hence they are small and also the resulting rock is fine grained

6 0

2 years ago

One billiard ball is shot east at 2.2 m/s. A second, identical billiard ball is shot west at 0.80 m/s. The balls have a glancing

Leona [35]

Answer:

(a). The speed of the first ball after the collision is 1.95 m/s.

(b). The direction of the first ball after the collision is 44.16° due south of east.

Explanation:

Given that,

Velocity of one ball u₁= 2.2i m/s

Velocity of second ball u₂=- 0.80i m/s

Final velocity of the second ball v₂= 1.36j m/s

The mass of the identical balls are

$m = m_{1}=m_{2}$

(a). We need to calculate the speed of the first ball after the collision

Using law of conservation of momentum

$m_{1}u_{1}+m_{2}u_{2}=m_{1}v_{1}+m_{2}v_{2}$

Along X- axis

$m_{1}u_{1}+m_{2}u_{2}=m_{1}v_{1}$

$v_{1}=u_{1}+u_{2}$

Put the value into the formula

$v_{1}=2.2i-0.80i$

$v_{1}=1.4i\ m/s$

Along Y-axis

$0=m_{1}v_{1}+m_{2}v_{2}$

$m_{1}v_{1}=-m_{2}v_{2}$

$v_{1}=-v_{2}$

Put the value into the formula

$v_{1}=-1.36j\ m/s$

Then the final speed of the first ball

$v_{1}=\sqrt{(1.4)^2+(1.36)^2}$

$v_{1}=1.95\ m/s$

(b) We need to calculate the direction of the first ball after the collision

Using formula of direction

$\tan\theta=\dfrac{v_{2}}{v_{1}}$

$\tan\theta=\dfrac{-1.36}{1.4}$

$\theta=\tan^{-1}\dfrac{-1.36}{1.4}$

$\theta=-44.16^{\circ}$

Negative sign shows the direction of first ball .

Hence, (a). The speed of the first ball after the collision is 1.95 m/s.

(b). The direction of the first ball after the collision is 44.16° due south of east.

7 0

3 years ago

Atoms are very small. Which measurement is the approximate diameter of a helium atom?

stich3 [128]

Atoms diameter are on the order of 60 to 600pm (picometers). This is around 6*10^-11.

3 0

3 years ago