3 years ago

How many atoms are in 26.8 g Fe

1 answer:

6 0

Answer:

2.881x10^23 atoms

Explanation:

From the studies of Avogadro's hypothesis, we discovered that 1mole of any substance contains 6.02x10^23 atoms.

Therefore 1mole of Fe contains 6.02x10^23 atoms.

Molar Mass of Fe = 56g/mol

56g of Fe contains 6.02x10^23 atoms.

Therefore, 26.8g of Fe will contain = (26.8x6.02x10^23) / 56 = 2.881x10^23 atoms

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