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garik1379 [7]
3 years ago
7

Which is the correct net ionic equation for the reaction of aqueous ammonia with nitric acid? Which is the correct net ionic equ

ation for the reaction of aqueous ammonia with nitric acid?NH3(aq) + NO3−(aq) → NH2−(aq) + HNO3(aq)NH4+(aq) + H+(aq) → NH52+(aq)NH2−(aq) + H+(aq) → NH3(aq)NH4+(aq) + NO3−(aq) → NH4NO3(aq)NH3(aq) + H+(aq) → NH4+(aq)
Chemistry
1 answer:
Svet_ta [14]3 years ago
4 0

Answer:

The last option:

  • NH₃ (aq) +  H⁺ (aq)  →  NH₄⁺ (aq)

Explanation:

1) Word equation

  • Aqueous ammonia + nitric acid → aqueous ammonium nitrate

2) Chemical (molecular) equation

  • NH₃ (aq) + HNO₃ (aq)  → NH₄ NO₃

3) Ionization reactions

Write the dissociation of the soluble ionic compounds:

  • HNO₃ → H⁺ + NO₃⁻
  • NH₄ NO₃ → NH₄⁺ + NO₃⁻

4) Total ionic equation:

  • NH₃ (aq) +  H⁺ (aq) + NO₃⁻ (aq) →  NH₄⁺ (aq) + NO₃⁻ (aq)

5) Net ionic equation

You must cancel the spectator ions, which are those ions that are repeated in both reactant and product sides, i.e. NO₃⁻. They are name spectator because they do not participate (change) during the reaction.

  • NH₃ (aq) +  H⁺ (aq)  →  NH₄⁺ (aq)

And that is the last choice of the list.

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An aqueous HCL solution has a proton concentration equal to 6.00 mol/L. The HCL concentration in this solution is ————M.
Harman [31]

Answer:

HCl conc.= 6.0mol/L

Explanation:

From the dissociation of HCl= 1 mole H+ and 1mol Cl-, which is equivalent stoichiometrically in concentration to that of 1 mol HCl,

4 0
4 years ago
Why can't helium bond with hydrogen?
Iteru [2.4K]
Hydrogen and Helium cannot bond together. Put aside the inertness of helium (or all noble gases), bond formation is only favored when the final state of the two elements is more stable than their initial state. ... Helium compounds has some predictions though none of them contain only those two elements.
8 0
3 years ago
Rusting of iron is a very common chemical reaction. It results in one form from Fe reacting with oxygen gas to produce iron (III
Vlada [557]

<u>Answer:</u> The given amount of iron reacts with 9.0 moles of O_2 and produce 6.0 moles of Fe_2O_3

<u>Explanation:</u>

We are given:

Moles of iron = 12.0 moles

The chemical equation for the rusting of iron follows:

4Fe+3O_2\rightarrow 2Fe_2O_3

  • <u>For oxygen gas:</u>

By Stoichiometry of the reaction:

4 moles of iron reacts with 3 moles of oxygen gas

So, 12.0 moles of iron will react with = \frac{3}{4}\times 12.0=9.0mol of oxygen gas

  • <u>For iron (III) oxide:</u>

By Stoichiometry of the reaction:

4 moles of iron produces 2 moles of iron (III) oxide

So, 12.0 moles of iron will produce = \frac{2}{4}\times 12.0=6.0mol of iron (III) oxide

Hence, the given amount of iron reacts with 9.0 moles of O_2 and produce 6.0 moles of Fe_2O_3

5 0
3 years ago
What is the pressure in a gas container that is connected to an open-end U-tube manometer if the pressure of the atmosphere is 7
mojhsa [17]

Answer:

636 mm Hg

Explanation:

The pressure in the gas container is equal to the atmospheric pressure minus the height of mercury:

Atmospheric pressure = 722 torr = 722 mm Hg

Height = 8.60 cm = 86 mm Hg

Pressure = 722 - 86 = 636 mm Hg

So none of the given options is correct, the correct answer is 636 mm Hg.

5 0
3 years ago
How many total atoms are in 0.530 g of P2O5/12131141/dc2696ff?utm_source=registration
Lyrx [107]
In order to calculate the number of atoms present in 0.53 grams of P₂O₅, first calculate the number of moles for given mass.

As, Moles is given as,

                             Moles  =  Mass / M.mass

                             Moles  =  0.53 g ÷ 283.88 g.mol⁻¹

                             Moles  =  0.00186 moles

Now calculate the number of Molecules present in calculated moles of P₂O₅.

As,
                        1 Mole of P₂O₅ contains  =  6.022 × 10²³ Molecules
So,
             0.00186 Moles of P₂O₅ contain  =  X Molecules

Solving for X,
                        X  =  (0.00186 mol × 6.022 × 10²³ Molecules) ÷ 1 mol

                        X  =  1.12 × 10²¹ Molecules

Also, in P₂O₅ there are 7 atoms, in 1.12 × 10²¹ Molecules there will be.....

                            = 1.12 × 10²¹ × 7

                            =  7.84 × 10²¹ Atoms
Result:
            
7.84 × 10²¹ Atoms are present in 0.53 grams of P₂O₅.
8 0
3 years ago
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