Given the mass of CO2 =15.02 g
Moles of
=
Mass of H2O = 2.458 g
Moles of
=
Moles of C = 
Moles of H = 
Mass of C in the sample = 
Mass of H =
=0.275 gH
Mass of O in the sample = 5.467 g - (4.095 g +0.275 g) = 1.097 g O
Moles of O = 
Simplest mole ratios of the elements in the compound:

Therefore the empirical formula of the compound is 
Answer:- 3.84 grams
Solution:- Volume of the sample is 44.8 mL and the density is 1.03 gram per mL.
From the density and volume we calculate the mass as:
mass = volume*density

= 46.1 g
From given info, potassium bromide solution is 8.34% potassium bromide by mass. It means if we have 100 grams of the solution then 8.34 grams of potassium bromide is present in. We need to calculate how many grams of potassium bromide are present in 46.1 grams of the solution.
The calculations could easily be done using dimensional analysis as:

= 3.84 g KBr
Hence, 3.84 grams of KBr are present in 44.8 mL of the solution.
Carboxylic acid...........
Boric acid, H3BO3, in aqueous solution would only give out one H+ ion. As it is also produce OH ion and by hydrolysis it produces one proton. <span>All the boron compounds (BX3) are having only 6 valence electrons in it and should follow the octet rule by taking another electron.</span>
B(OH)3 + 2 H2O → B(OH)4− + H3O
Answer:
construct using only recycled materials ^^
Explanation: