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Murljashka [212]
4 years ago
11

Describe the buffer capacity of the acetic acid buffer solution in relation to the addition of both concentrated and dilute acid

s and bases.
Chemistry
1 answer:
AysviL [449]4 years ago
5 0

Answer:

The answer is in the explanation

Explanation:

Acetic acid, CH₃COOH, is a weak acid that will produce a buffer when its conjugate base, CH₃COO⁻, acetate ion, is added to the solution.

<em>That is because a buffer is the mixture of a weak acid and its conjugate base or vice versa.</em>

When an acid (HX) is added to the solution, the acetate ion will react producing acetic acid, thus:

CH₃COO⁻ + HX → CH₃COOH + X⁻

For this reason, the pH doesn't change abruptly because H⁺ ions are not produced.

Now, if a  base (BOH) is added to the buffer, CH₃COOH will react producing acetate ion and water, thus:

CH₃COOH + BOH → CH₃COO⁻ + H₂O + B⁺.

In the same way, there are not produced free OH⁻ and the pH doesn't change significantly.

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22 g de um gás estão contidos em um recipiente de volume igual a 17,5 L, a uma temperatura de 77ºC e
Aleksandr-060686 [28]

Answer:

Option D.

Explanation:

Let's apply the Ideal Gases law to solve the problem.

P . V = n . R . T

First of all we convert the temperature value from °C to K

77°C + 273 = 350K

and the pressure from mmHg to atm

623 mmHg .  1 atm/760 mmHg = 0.82 atm

We replace data: 0.82 atm . 17.5L = n . 0.082 L.atm/mol.K . 350K

(0.82 atm . 17.5L) / (0.082 L.atm/mol.K . 350K) = n

0.50 moles = n

These are the moles that corresponds to 22 g of the gas, so the molar mass will be → 22g / 0.50 mol =  44 g/mol

That molar mass corresponds to CO₂  →  12 g (C) + 16 g (O) . 2 = 44 g/mol

4 0
3 years ago
When calcium metal (Ca) reacts with oxygen gas (O2), it produces the ionic compound calcium oxide (CaO). Write the balanced equa
jonny [76]

Oxidation-Reduction Reactions Suggested Reading Thus the oxidation number for oxygen in calcium oxide is -2. ... In effect, each calcium atom loses two electrons to form Ca2+ ions, and each O atom in O2 gains two electrons to form O2- ions. The net result is a transfer of electrons from calcium to oxygen, so this reaction is an oxidation-reduction reaction.

+<u>O²</u><u>(</u><u>g</u><u>)</u><u>=</u><u>2</u><u>CaO</u><u>(</u><u>s</u><u>)</u>

Explanation:

we can conclude that in the reaction there is both reduction and oxidation.

6 0
3 years ago
A 1.93-mol sample of xenon gas is maintained in a 0.805-L container at 306 K. Calculate the pressure of the gas using both the i
Alex

Answer : The pressure of the gas using both the ideal gas law and the van der Waals equation is, 60.2 atm and 44.6 atm respectively.

Explanation :

First we have to calculate the pressure of gas by using ideal gas equation.

PV=nRT

where,

P = Pressure of Xe gas = ?

V = Volume of Xe gas = 0.805 L

n = number of moles Xe = 1.93 mole

R = Gas constant = 0.0821L.atm/mol.K

T = Temperature of Xe gas = 306 K

Now put all the given values in above equation, we get:

P\times 0.805L=1.93mole\times (0.0821L.atm/mol.K)\times 306K

P=60.2atm

Now we have to calculate the pressure of gas by using van der Waals equation.

(P+\frac{an^2}{V^2})(V-nb)=nRT

P = Pressure of Xe gas = ?

V = Volume of Xe gas = 0.805 L

n = number of moles Xe = 1.93 mole

R = Gas constant = 0.0821L.atm/mol.K

T = Temperature of Xe gas = 306 K

a = pressure constant = 4.19L^2atm/mol^2

b = volume constant = 5.11\times 10^{-2}L/mol

Now put all the given values in above equation, we get:

(P+\frac{(4.19L^2atm/mol^2)\times (1.93mole)^2}{(0.805L)^2})[0.805L-(1.93mole)\times (5.11\times 10^{-2}L/mol)]=1.93mole\times (0.0821L.atm/mol.K)\times 306K

P=44.6atm

Therefore, the pressure of the gas using both the ideal gas law and the van der Waals equation is, 60.2 atm and 44.6 atm respectively.

5 0
3 years ago
What bias conditions must be present for the normal operation of a transistor amplifier? A. The emitter-base junction must be fo
natali 33 [55]
The answer would be A. which says the emitter- base junction must be forward biased, and the collector- base junction must be reverse biased.
8 0
3 years ago
Which of the following molecules has only single bonds?
mel-nik [20]

Answer:

C

Explanation:

it only bonded with one other molecule carbon/ oxgen=carbon dioxide

6 0
4 years ago
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