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kotykmax [81]
3 years ago
9

30 POINTS PLEASE HELP

Mathematics
1 answer:
Tatiana [17]3 years ago
8 0

1. There was 20% error.

2. There was 5.33% error.

Step-by-step explanation:

1. Jerri estimated that 30 people would attend the dinner event, but only 25 people attended.

Exact value = 25

Approx value = 30

Percent error = \frac{|approx-exact|}{exact}*100

Percent error = \frac{|30-25|}{25}*100 = \frac{|5|}{25}*100

Percent error = \frac{500}{25} = 20\%

There was 20% error.

2. Gene estimated the length of the fence to be 150 feet, but the actual measurement was 142.

Exact value = 142 feet

Approx value = 150 feet

Percent error = \frac{|150-142|}{150}*100 = \frac{|8|}{150}*100

Percent error = \frac{800}{150} = 5.33\%

There was 5.33% error.

Keywords: Error, percentage

Learn more about percentages at:

  • brainly.com/question/10435816
  • brainly.com/question/10435836

#LearnwithBrainly

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Answer:

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Step-by-step explanation:

Let he bought c packages of chocolate bars and t packages of toffee bars,

Since, he bought 1 fewer package of chocolate bars than toffee bars.

⇒ c = t - 1  -----(1)

Also, he handed out out \frac{2}{3} of the chocolate bars and \frac{3}{5} of the toffee bars,

If he handed out the same number of each kind of candy bar.

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1=\frac{10c-9c}{9}

1=\frac{c}{9}

\implies c = 9

Hence, he bought 9 packages of chocolate bars.

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