Answer:
60 minutes for the larger hose to fill the swimming pool by itself
Step-by-step explanation:
It is given that,
Working together, it takes two different sized hoses 20 minutes to fill a small swimming pool.
takes 30 minutes for the larger hose to fill the swimming pool by itself
Let x be the efficiency to fill the swimming pool by larger hose
and y be the efficiency to fill the swimming pool by larger hose
<u>To find LCM of 20 and 30</u>
LCM (20, 30) = 60
<u>To find the efficiency </u>
Let x be the efficiency to fill the swimming pool by larger hose
and y be the efficiency to fill the swimming pool by larger hose
x = 60/30 =2
x + y = 60 /20 = 3
Therefore efficiency of y = (x + y) - x =3 - 2 = 1
so, time taken to fill the swimming pool by small hose = 60/1 = 60 minutes
Answer:
3(4+x)
which can be simplified to 12+3x
Answer:
A.
-19 9 7
[15 -7 6 ]
-2 1 1
Step-by-step explanation:
your answer is (1,3) but positive
Answer:
A = 72°
B = 108°
Step-by-step explanation:
5y - 3 = 3y + 27
5y - 3y = 27 + 3
2y = 30
y = 30/2
y = 15
A = 5y - 3
A = 5(15) - 3
A = 75 - 3
A = 72°
A + B = 180°
72° + B = 180°
B = 180° - 72°
B = 108°
