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stich3 [128]
3 years ago
13

I need help please!!!!

Mathematics
1 answer:
Nataly [62]3 years ago
3 0
The answer to the problem I think is a>-4.
You have to flip it if it is a negative. I could be wrong..
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Evaluate n + m when n = -24 and y = 0.874.
Flauer [41]

Answer:

-24+m is correct answer

Step-by-step explanation:

In pic

(Credit : Symbolab)

(Hope this helps can i pls have brainlist (crown)☺️)

3 0
3 years ago
$15,000 is invested at a rate of 8% compounded quarterly. Identify the compound interest function to model the situation. Then f
Rina8888 [55]

Answer:

A = 15000(1.02)^4t ; $33,120.59

7 0
2 years ago
Someone pls help me solve this ;-;
Mazyrski [523]
5∛x + 4 = 44
5∛x = 40
  ∛x = 8
    x = 8^3
    x = 512

answer
C. 512
8 0
3 years ago
Help!! need this asap
lesya [120]

Answer:

A≈21.46

<em>Hope Helps </em>

<em>:)</em>

8 0
3 years ago
Help me please and thank you
sdas [7]

Answer:

Based on the model, the length of the wall is \frac{9}{8} ft, the width of the wall is \frac{1}{2} ft,  and the height of the wall is \frac{11}{8} ft. The volume of the portion of security wall that  Tim has constructed so far is \frac{99}{128}  cu ft.

Step-by-step explanation:

Given:

The figure constructed shows a rectangular prism made up of small wooden cubes of length \frac{1}{8}\ ft.

Width of the prism = \frac{1}{2}\ ft.

To find length , height and volume of the figure.

Solution:

From the figure we can conclude that :

Length side of the prism counts 9 cubes.

Thus, length of the prism will be given as :

⇒ \textrm{Length of each cube}\times \textrm{Number of cubes}

⇒ \frac{1}{8}\ ft\times 9

⇒ \frac{9}{8}\ ft  (Answer)

Height side of the prism counts 11 cubes.

Thus, height of the prism will be given as :

⇒ \textrm{Length of each cube}\times \textrm{Number of cubes}

⇒ \frac{1}{8}\ ft\times 11

⇒ \frac{11}{8}\ ft (Answer)

Volume of the prism can be given as :

⇒ Length\times width\times height

⇒ \frac{9}{8}\ ft\times \frac{1}{2}\ ft\times \frac{11}{8}\ ft

⇒ \frac{99}{128}\ ft^3 (Answer)

7 0
3 years ago
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